Positronium allowed decays (Peskin)

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In summary, the conversation discusses the decay of spin 0 and spin 1 positronium ground states into photons, and the role of Parity and Charge conjugation in this process. The solution involves considering the interaction matrix term and evaluating the P and C eigenvalues of states containing only photons. A solution has been provided by someone else.
  • #1
Hao
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Homework Statement


(This is not homework)
This refers to question 3.8 in Peskin's QFT

Using the fact that the electromagnetic interaction term in the Dirac + EM lagrangian is invariant under Parity (P) and Charge conjugation (C), and that spin 0 and spin 1 states are odd and even under exchange of spins,

show that the
1) spin 0 positronium ground state (S wavefunction) decays into 2 photons, and that the
2) spin 1 positronium ground state (S wavefunction) must decay into 3 photons
3) The above for P, D states.


Homework Equations



EM coupling
[tex]\Delta H=\int A_{\mu}j^{\mu}d^{3}x[/tex]

We know that under parity, [tex]j^{\mu}\rightarrow (j^{0},-j^{1},-j^{2},-j^{3})[/tex]
We know that under parity, [tex]j^{\mu}\rightarrow -j^{\mu}[/tex]

The Attempt at a Solution



By handwaving, we can say that these transitions occur due to conservation of angular momentum as a photon has a spin of 1.

However, how would these transitions be derived on the basis of C and P symmetries alone?

One could probably consider the interaction matrix term:

[tex]\left\langle photons\right|\Delta H\left|positronium\right\rangle[/tex]

And determine how it transforms under C and P

The problem I have is in evaluating the P and C eigenvalues of states that contain only photons.

For a state involving a fermion and antifermion (eg. positronium), and with orbital angular momentum L, P|state> = (-1)L+1|state>. The extra factor of +1 is due to the anticommutativity of spin 1/2 creation operators.

Thanks
 
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  • #2
For those who are interested, I've found a solution by somebody else.

http://www.maths.tcd.ie/~powersr/New/
 

Related to Positronium allowed decays (Peskin)

1. What is Positronium?

Positronium is a unique atom-like system that consists of an electron and a positron (the antimatter counterpart of an electron) bound together by the electromagnetic force. It is the lightest known atom and has properties similar to hydrogen.

2. How do Positronium allowed decays occur?

Positronium allowed decays occur when the bound state of an electron and a positron is broken, resulting in the release of energy in the form of photons. This can happen through two different processes: annihilation, where the electron and positron collide and produce two or more photons, or decay, where the positronium spontaneously breaks down into two photons.

3. What are the different types of Positronium allowed decays?

The two main types of Positronium allowed decays are para-Positronium and ortho-Positronium. Para-Positronium has the electron and positron in an antisymmetric spin state, while ortho-Positronium has them in a symmetric spin state. These two states have different energy levels and thus can decay into different numbers of photons.

4. What is the significance of Positronium allowed decays in particle physics?

Positronium allowed decays are important in understanding the fundamental interactions of particles and the properties of the vacuum. They also provide a unique way to study antiparticles and their behavior, which can shed light on the asymmetry between matter and antimatter in the universe.

5. What is the Peskin rule for calculating Positronium allowed decays?

The Peskin rule, named after physicist Michael Peskin, is a simple formula used to calculate the decay rate of ortho-Positronium into two photons. It states that the decay rate is proportional to the square of the fine structure constant, the mass of the electron, and the cube of the energy level of ortho-Positronium. This rule has been experimentally verified and is widely used in theoretical calculations of Positronium allowed decays.

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