Projectile motion from the ground

In summary, the conversation discusses problem 5.9 and its given data, as well as equations and variables used in the problem. It is clarified that the variable 's' represents distance, and the subscript 'y' refers to the vertical direction. The value of -32 ft/s^2 is used for gravitational acceleration in this problem. The conversation also addresses the final position of the object and its distance in the vertical direction.
  • #1
Scorry
17
1

Homework Statement



The problem (5.9) and given data is attached.

Homework Equations


All relevant equations are given (5.9).

On (5.9) What does the s subscript y represent? And why does gravity equal -32?

The Attempt at a Solution


The solution is given. This is a scan problem.
 

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  • #2
They are using the variable s to represent distance (This is a common practice in some texts). So ##s_y## would be the distance in the "y" (vertical) direction. ##32 ft/s^2## is the gravitational acceleration using feet rather than meters for distance.
 
  • #3
Thank you gneill. Is the distance in the "y" vertical direction 0 because its final position is the ground?
 
  • #4
Scorry said:
Thank you gneill. Is the distance in the "y" vertical direction 0 because its final position is the ground?
It's 0 at the beginning and end of the trajectory, both at ground level.
 

Related to Projectile motion from the ground

What is projectile motion from the ground?

Projectile motion from the ground is the movement of an object that is launched from a horizontal surface, such as the ground. It follows a curved path due to the influence of gravity and the initial velocity of the object.

What factors affect projectile motion from the ground?

The factors that affect projectile motion from the ground include the initial velocity of the object, the angle at which it is launched, and the force of gravity. Other factors such as air resistance and wind can also play a role.

How is the trajectory of a projectile calculated?

The trajectory of a projectile can be calculated using the equations of motion, which take into account the initial velocity, angle of launch, and acceleration due to gravity. These equations can be solved using mathematical methods or by using computer software.

What is the maximum height of a projectile?

The maximum height of a projectile is reached when the vertical component of its velocity becomes zero. This can be calculated using the equation h = (v^2 * sin^2θ) / (2g), where h is the maximum height, v is the initial velocity, θ is the angle of launch, and g is the acceleration due to gravity.

How can projectile motion from the ground be applied in real life?

Projectile motion from the ground has many practical applications, such as in sports like basketball and baseball where the trajectory of a ball needs to be calculated for accurate shots. It is also used in military operations, such as the trajectory of a missile or bomb. In addition, it is an important concept in physics and engineering for understanding the motion of objects in 2-dimensional space.

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