Proving Linear Independence of vectors

In summary, the question is asking to show that the given vectors x1, x3, and x4 are linearly independent. By setting up and solving an augmented matrix for the equation ax1+bx2+cx3+dx4=0, it is found that the vectors are linearly dependent. This is because the number of leading entries in the row reduced matrix is not equal to the number of unknowns, indicating that there is a non-trivial solution. Therefore, x1, x3, and x4 cannot be linearly independent.
  • #1
zecuria
3
0

Homework Statement



Let x1 = (1, 2, -1, 1), x2 = (-1, -1, -1, -1), x3 = (1, 1, 1, 0), x4 = (-2, -1 -4 -1)

Show that x1, x3 and x4 are linearly independent



Homework Equations





The Attempt at a Solution


Now I used the equation:
ax1+bx2+cx3+dx4=0

Hence forth the augmented matrix of the equation is,

[tex]
\begin{pmatrix}
1 & -1 & 1 & -2 & | & 0\\
2 & -1 & 1 & -1 & | & 0\\
-1 & -1 & 1 & -4 & | & 0\\
1 & -1 & 0 & -1 & | & 0
\end{pmatrix}
[/tex]

This is row reduced to,

[tex]
\begin{pmatrix}
1 & -1 & 1 & -2 & | & 0\\
0 & 1 & -1 & 3 & | & 0\\
0 & 0 & -1 & 1 & | & 0\\
0 & 0 & 0 & 0 & | & 0
\end{pmatrix}
[/tex]

From as there is no leading entry corresponding to d, Setting d = t, the general solution is:

a = -t, b = -2t, c = t, d = t.

And as the number of leading entries =! number of unknowns so the vectors are linearly dependant

This is the point where I get confused as the question asks how they are linearly independant so I am quite confused at this point

Any help would be most appreciated and thanks in advanced
 
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  • #2
zecuria said:

Homework Statement



Let x1 = (1, 2, -1, 1), x2 = (-1, -1, -1, -1), x3 = (1, 1, 1, 0), x4 = (-2, -1 -4 -1)

Show that x1, x3 and x4 are linearly independent


You have to show that x1,x2,x4 are linearly independent. Do the Gauss elimination with these three vectors.

ehild
 

1. What does it mean for vectors to be linearly independent?

Linear independence refers to a set of vectors that cannot be expressed as a linear combination of each other. In other words, no vector in the set can be written as a combination of the other vectors in the set using scalar multiplication and addition.

2. How do you prove that a set of vectors is linearly independent?

To prove linear independence, you must show that there is no non-trivial solution to the equation c1v1 + c2v2 + ... + cnvn = 0, where c1, c2, ... cn are coefficients and v1, v2, ... vn are vectors in the set. This can be done by setting up a system of equations and solving for the coefficients, or by using other methods such as the determinant test or the rank-nullity theorem.

3. What is the difference between linearly independent and linearly dependent vectors?

Linearly independent vectors cannot be written as a linear combination of each other, while linearly dependent vectors can. In other words, linearly dependent vectors are redundant and do not add any new information to the set.

4. Can a set of two or more vectors be linearly independent in one context and linearly dependent in another?

Yes, the linear independence of a set of vectors depends on the context and the vector space in which they are being considered. For example, a set of two vectors may be linearly independent in a three-dimensional space, but linearly dependent in a two-dimensional space.

5. Why is it important to prove linear independence of vectors?

Proving linear independence is important because it helps determine the dimension of a vector space and whether a set of vectors forms a basis for that space. It also has applications in various fields of mathematics and science, such as in solving systems of equations and studying linear transformations.

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