Question on car speed and distance.

In summary, a car with constant acceleration covers 58m in 6.2 seconds and has a speed of 54 km/hr at the second point. Using kinematic equations and conversions, the speed at the first point can be calculated to be 30.33 km/hr. As for the distance from the first point where the car was at rest, more information or equations are needed to determine this.
  • #1
wolfgangjt
8
0

Homework Statement


A car moving at constant acceleration covers the distance between two points 58m apart in 6.2 seconds. its speed as it passes the second point is 54 km/hr. what is the speed at the first point? at what prior distance from the first point was the car at rest?

Homework Equations


Conversions.
58m/6.2s =9.36m/s 9.36 m/s converts to .5616km/hr. 54 km/hr * .5616km/hr = 30.33 km/hr

The Attempt at a Solution


The speed at the first point is 30.33 KM/Hr. Not sure how to arrive at the second part.
 
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  • #2
wolfgangjt said:

Homework Statement


A car moving at constant acceleration covers the distance between two points 58m apart in 6.2 seconds. its speed as it passes the second point is 54 km/hr. what is the speed at the first point? at what prior distance from the first point was the car at rest?


Homework Equations


Conversions.
58m/6.2s =9.36m/s 9.36 m/s converts to .5616km/hr. 54 km/hr * .5616km/hr = 30.33 km/hr

The Attempt at a Solution


The speed at the first point is 30.33 KM/Hr. Not sure how to arrive at the second part.

What kinematic equations are you using?

And what have you been given in the question?
 

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