Radioactive Decay - working out activity

[FaraDazed]

Homework Statement

If you have 500g of Thorium-234 at t=0. Calculate the initial activity and the activity after 2 weeks. The half life of thorium-234 is 24 days.

Homework Equations

$A=A_0e^{-\lambda t} \\ A_0=\lambda N_0 \\ \lambda=\frac{ln2}{t_{\frac{1}{2}}}$

The Attempt at a Solution

For the intial activity I first found lambda by converting 24 days into seconds.

$\lambda=\frac{ln2}{60 \times 60 \times 24 \times 24}=\frac{ln2}{2073600}=3.34 \times 10^{-7} \\$

Then used the second relevant equation listed above by calculating N_0 with the known data (converting to number of moles and then times by Avogadros number).
$A_0=\lambda N_0=(3.34 \times 10^{-7})(\frac{500}{234})(6.02 \times 10^{23})=4.29 \times 10^{17} Bq$

Then after knowing A_0 i can calculate the activity after 2 weeks, with the first relevant equation listed but converting 2 weeks into seconds.
$A=A_0e^{-\lambda t}=(4.29 \times 10^{17})e^{(3.34 \times 10^{-7})(1209600)}=2.86 \times 10^{17} Bq$

My problem is with my answers, they seem way way too high. I was told in a lecture it is very unusual to ever go above a micro Bq.

 

[Curious3141]

Haven't checked the math, but I think you have it the other way around, a Bq is a very small unit of radioactivity. It's true that background counts should be less than a Bq, but when you're talking about radioisotopes, you're definitely talking about much more than a Bq.

 

[FaraDazed]

Haven't checked the math, but I think you have it the other way around, a Bq is a very small unit of radioactivity. It's true that background counts should be less than a Bq, but when you're talking about radioisotopes, you're definitely talking about much more than a Bq.

Right, that could be it. He was talking about a unit called the curie too at the same time but didnt quite understand what he said as he went over it very quickly but from what he said I got the impression that 1Bq=1Cu but that they usually say Bq these days.

It may be that they are not equal and that he meant that its unusual to ever get a reading of over 1Cu and not 1Bq.

 

[Curious3141]

Right, that could be it. He was talking about a unit called the curie too at the same time but didnt quite understand what he said as he went over it very quickly but from what he said I got the impression that 1Bq=1Cu but that they usually say Bq these days.

It may be that they are not equal and that he meant that its unusual to ever get a reading of over 1Cu and not 1Bq.

A Cu is a MUCH bigger unit than a Bq.

27pCu (that's picoCurie)= 1Bq

 

[FaraDazed]

A Cu is a MUCH bigger unit than a Bq.

27pCu (that's picoCurie)= 1Bq

That makes sense then and why my answers are so high, I was getting Bq and Cu mixed up. Do you think my answers are correct?

 

[lightgrav]

yes, they sound ok ... if you would ever have 500 grams of 234Th!
(why do you use "Bq" if it is confusing, rather than the straightforward "decay/sec")