It will be the equation for a straight lineDeckSmeck said:I fly in a spaceship on a 2d plane (for simplicity sake) in zero G. I eject a rock 90 degrees right to my forward vector. What does the equation look like if I want the final vector of the rock?
To get the exact equation, you'll need the speed of your ship and the speed with which you eject the rock (and to be fully accurate, the place on the graph where the rock gets ejected, but for simplicity you could just take that as being the origin.What variables need to be known about the ship and rock?
phinds said:It will be the equation for a straight line
To get the exact equation, you'll need the speed of your ship and the speed with which you eject the rock (and to be fully accurate, the place on the graph where the rock gets ejected, but for simplicity you could just take that as being the origin.
If, on the other hand, you were "ejecting a photon", you would get a completely different result. It would still be a straight line, but it would be just a horizontal line since the motion of your ship would have no effect on the photon.
speed or velocity WHAT ?DeckSmeck said:Speed or velocity?
phinds said:If, on the other hand, you were "ejecting a photon", you would get a completely different result. It would still be a straight line, but it would be just a horizontal line* since the motion of your ship would have no effect on the photon.
* I'm assuming your ship is traveling in the postie Y direction.
I understand these terms describe different things.phinds said:speed or velocity WHAT ?
And what is it that you want to know about as regards this thread. Your postDeckSmeck said:I understand these terms describe different things.
was meaningless to me.DeckSmeck said:Speed or velocity?
phinds said:And what is it that you want to know about as regards this thread. Your post
was meaningless to me.
The equation is utterly trivial. If the plane is flying in the postive Y direction with velocity v1 and the rock is ejected to the right with velocity v2 as the plane passes the origin, then the equation is y=(v1/v2)xDeckSmeck said:Ok. Maybe someone else can come up with an equation. I will check tommorrow.
I recommend reading this link on vector addition:DeckSmeck said:I fly in a spaceship on a 2d plane (for simplicity sake) in zero G. I eject a rock 90 degrees right to my forward vector. What does the equation look like if I want the final vector of the rock?
I know the final speed of the rock is 100.
What variables need to be known about the ship and rock?
You will get better responses if you write your questions in complete sentences, containing complete thoughts. I believe I know what this question was referring to, but you should have written it out fully.Speed or velocity?
Rocks can be ejected from a spaceship due to the force of the spaceship's engines or from collisions with other objects in space.
Yes, the speed of the spaceship can greatly impact the ejection of rocks. The faster the spaceship is traveling, the more force is exerted on the rocks, causing them to be ejected at a higher velocity.
The distance that rocks can be ejected from a spaceship depends on a variety of factors, such as the speed of the spaceship, the size of the rocks, and any external forces acting on the rocks. In some cases, rocks have been known to travel thousands of kilometers away from a spaceship.
Yes, ejected rocks can pose a hazard for other spaceships or objects in space. If they collide with another object, they can cause damage or alter the object's trajectory. It is important for spaceships to carefully monitor and control the ejection of rocks to avoid potential collisions.
Yes, rocks ejected from a spaceship can be incredibly valuable for scientific research. They can provide insights into the composition and formation of other planets or bodies in our solar system. Scientists can analyze the rocks to learn more about the history and evolution of our universe.