- #1
Moneer81
- 159
- 2
Hey,
I need some guidance in this problem. Consider a rocket taking off vertically from rest in a gravitational field g, the equation of motion (which I had to derive in the previous part of this problem) is:
[tex]
m \dot{v} = -\dot{m}v_{ex} - mg
[/tex]
where
m is the mass of the rocket
[tex] v_{ex} [/tex] is the the speed at which the exhaust fuel is being ejected relative to the rocket
Also, assume that the rocket is ejecting mass at a constant rate, so [tex] \dot{m}=-k [/tex] (where k is a positive constant) so that [tex]m = m_{0} - kt [/tex]
Solve the equation for v as a function of t, using separation of variables (rewriting the equation so that all the terms involving v are on the left and all the terms involving t on the right)
Now what is confusing me is at what point to I have to substitute for
[tex] \dot{m} [/tex] and m ?
Can I start by saying, [tex] m \frac{dv}{dt} = k v_{ex} - mg [/tex]
and then plug in [tex] m = m_{0} - kt [/tex] and take it from here?
I need some guidance in this problem. Consider a rocket taking off vertically from rest in a gravitational field g, the equation of motion (which I had to derive in the previous part of this problem) is:
[tex]
m \dot{v} = -\dot{m}v_{ex} - mg
[/tex]
where
m is the mass of the rocket
[tex] v_{ex} [/tex] is the the speed at which the exhaust fuel is being ejected relative to the rocket
Also, assume that the rocket is ejecting mass at a constant rate, so [tex] \dot{m}=-k [/tex] (where k is a positive constant) so that [tex]m = m_{0} - kt [/tex]
Solve the equation for v as a function of t, using separation of variables (rewriting the equation so that all the terms involving v are on the left and all the terms involving t on the right)
Now what is confusing me is at what point to I have to substitute for
[tex] \dot{m} [/tex] and m ?
Can I start by saying, [tex] m \frac{dv}{dt} = k v_{ex} - mg [/tex]
and then plug in [tex] m = m_{0} - kt [/tex] and take it from here?
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