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Whatupdoc
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[tex]\int 96cos^4(6x) * dx[/tex]
ok first i take out the 96 cause it's constant!
[tex] 96 \int cos^4(6x) * dx[/tex]
[tex] 96 \int (cos^2(6x)^2) * dx [/tex]
ok now with that setup, i can know use the half-angel formula!
[tex] 96 \int (\frac{1+cos(12x)}{2})^2 [/tex]
squared the problem...
[tex] 24 \int (1+ 2cos(12x) + (cos12x)^2 [/tex]
now to use the half-angle idents agian..
[tex] 24 \int 1 +2cos(12x) + 1/2(1+cos24x) [/tex]
can someone tell me if I am doing this correctly before i integral the problem?
ok first i take out the 96 cause it's constant!
[tex] 96 \int cos^4(6x) * dx[/tex]
[tex] 96 \int (cos^2(6x)^2) * dx [/tex]
ok now with that setup, i can know use the half-angel formula!
[tex] 96 \int (\frac{1+cos(12x)}{2})^2 [/tex]
squared the problem...
[tex] 24 \int (1+ 2cos(12x) + (cos12x)^2 [/tex]
now to use the half-angle idents agian..
[tex] 24 \int 1 +2cos(12x) + 1/2(1+cos24x) [/tex]
can someone tell me if I am doing this correctly before i integral the problem?
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