- #1
apiwowar
- 96
- 0
the top and bottom margins of a poster are 2cm and the side margins are each 4cm. If the area of printed material on the poster is fixed at 382 square centimeters, find the dimensions of the poster with the smallest area.
so the area l*w = 382
and the perimiter = 2(l-4)+2(w-8)
but if i try to solve for l i get a negative number. can someone help me out?
so the area l*w = 382
and the perimiter = 2(l-4)+2(w-8)
but if i try to solve for l i get a negative number. can someone help me out?