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Homework Statement
A beam of mass 10.0 kg, is suspended from the ceiling by a single rope. It has a mass 40.0 kg attached at one end and a mass of 14.9 attached at the other. The beam has a length of L = 3 m, it is in static equilibrium, and it is horizontal. The tension in the rope is T = 637 N.
Determine the distance, x, from the left end of the beam to the point where the rope is attached
Homework Equations
Torque = Force Distance
3 = x1 +x2
The Attempt at a Solution
40 (X1) = 14.9 (X2) (since it's in equilibrium)
40 (3-X2) = 14.9 (X2)
120 - 40(X2) = 14.9 (X2)
120 = 54.9 (X2)
2.186 = X2
I have the feeling that I'm going to feel like an idiot once someone points out the problem with this to me...