Solving Circular Motion Qs: Flea on a Record & Pilot in a Loop

In summary, the centripetal force is 6.7*10^-5N when the plane is flying in a vertically oriented circular loop.
  • #1
crosbykins
53
0
URGENT: circular motion qs

Homework Statement



1. A 0.20g flea sits at a distance of 5.0cm from the centre of a rotating record.
a) If the record rotates at 77rpm, what is the centripetal force.
b) For the flea to remain at this spot, what must be its frictional force?

2. A pilot of mass 60.0kg is flying her plane in a vertically oriented circular loop. Just at the bottom of the loop, the plane's speed is 1.8*10^2km/h and the pilot feels exactly four times as heavy as she normally does.
a) What is the radius of the loop.
b)At what speed must she be flying at the top of the loop in order to feel weightless?

Homework Equations



Fnet = 4pi^2mrf^2
Fnet = mv^2/r

The Attempt at a Solution


a)
77rpm * (1/60s)
=1.3s^-1

Fnet=4pi^2(.0002kg)(.005m)(1.3s^-1)^3
=6.7*10^-5N

Therefore, the centripetal force is 6.7*10^-5N

b)
For the flea to stay in the same spot the firction must be 6.7*10^-5N also.

2.
a)
4mg = mv^2/r
r = v^2/4mg
=64m

Therefore, the radius is 64m.

b)
mg=mv^2/r
[(60.0kg)(9.8m/s^2)(64m)]/60.0kg =v^2
25m/s=v

Therefore, she must be flying at a speed of 25m/s.
 
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  • #2


There's no question; Can't be all that urgent!
 
  • #3


gneill said:
There's no question; Can't be all that urgent!

It's urgent because i think i did it all wrong...
 
  • #4


In the first question I think one problem stems from rounding intermediate results. Leave some more digits on the frequency that you calculated (it's an intermediate value -- part of the process, not the end result) round results to the required significant figures. You've also got a problem with your conversion of cm to m for the radius -- check the order of magnitude.

For the second question you need to pay attention to what forces are acting when. In particular, at the bottom of the loop the centripetal force due to the plane's motion is acting as well as the force due to gravity.
 
  • #5


gneill said:
In the first question I think one problem stems from rounding intermediate results. Leave some more digits on the frequency that you calculated (it's an intermediate value -- part of the process, not the end result) round results to the required significant figures. You've also got a problem with your conversion of cm to m for the radius -- check the order of magnitude.

For the second question you need to pay attention to what forces are acting when. In particular, at the bottom of the loop the centripetal force due to the plane's motion is acting as well as the force due to gravity.

for part b of qs 2, isn't the pilot experiencing weightlessness so the Fn would be 0 and the only other force is Fgrav?
 
  • #6


If the net force is zero, then the sum of all forces is zero.
 
  • #7


gneill said:
If the net force is zero, then the sum of all forces is zero.

this is really confusing, is it possible you write write out a step-by-step solution only to 2. b)? if not it's ok, thanks for the help
 
  • #8


gneill said:
If the net force is zero, then the sum of all forces is zero.

i meant Fnormal is 0, so the only force acting on the pilot when she is at the bottom is gravity
 
  • #9


If the plane is flying in a circular loop, then centripetal force will always be acting. Gravity, too, is always acting. The only difference between the top and bottom of the the loop is the relative directions of these forces, and, of course, the magnitude of the centripetal force if the velocity changes.

Draw free body diagrams for the forces in each case. Then do the sums.
 

Related to Solving Circular Motion Qs: Flea on a Record & Pilot in a Loop

1. What is circular motion?

Circular motion is the movement of an object along a circular path. It occurs when an object's velocity is constantly changing in direction, but its speed remains constant.

2. How do you calculate the centripetal force in circular motion?

The centripetal force can be calculated using the equation Fc = mv²/r, where Fc is the centripetal force, m is the mass of the object, v is the velocity, and r is the radius of the circular path.

3. What is the difference between centripetal force and centrifugal force?

Centripetal force is the force that keeps an object moving along a circular path, directed towards the center of the circle. Centrifugal force, on the other hand, is a fictitious or apparent force that seems to push an object away from the center of the circle.

4. How does the radius of the circular path affect the centripetal force?

The centripetal force is directly proportional to the radius of the circular path. This means that as the radius increases, the centripetal force also increases. As the radius decreases, the centripetal force decreases.

5. What is the relationship between tangential velocity and centripetal acceleration in circular motion?

The tangential velocity and centripetal acceleration are directly proportional in circular motion. This means that as the tangential velocity increases, the centripetal acceleration also increases. As the tangential velocity decreases, the centripetal acceleration decreases.

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