- #1
jmb07
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An object 1.95 cm high is placed 11.2 cm in front of a convex mirror with a radius of curvature of 9.8 cm. Where is the image formed??
So i know Di= (Doxf)/(Do+f)...(11.2 x 9.8)/ (11.2 + 9.8) = 5.23 cm
However, the correct answer is 3.41 cm
What am i doing wrong here? I know that the 9.8 may not be the focal length but how do i relate the height to the focal length??
So i know Di= (Doxf)/(Do+f)...(11.2 x 9.8)/ (11.2 + 9.8) = 5.23 cm
However, the correct answer is 3.41 cm
What am i doing wrong here? I know that the 9.8 may not be the focal length but how do i relate the height to the focal length??