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Quazswed
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Homework Statement
A particle traveling at 8 E7 m/s is accelerated so that its momentum doubles. What is the final velocity of the particle?
Homework Equations
p=ym0v
y= 1 / sqr(1-(v/c)^2)
p2= 2(p1)
Where p2 is the final momentum and p1 the initial
The Attempt at a Solution
For the initial velocity gamma=1,0376
p1 is therefore, calculated with m0=1 (I put it this way thinking it was not relevant to the problem, and it was meant to be eliminated when finding p2) 83008000 kg m/s
I tried to compare the two equations for the relativistic momentum but the best i came up with was that (v2)x(y2)=166016000 m/s
Given that the result written on the book is 1,5 E8 m/s, y2 must be 1,107
because y2= 2y1v1 / v2
But for a velocity of 1,5 E8 m/s (0,5c), the dilatation factor is 1,154
I really don't know, I keep trying the same method, I can't see a different way to resolve it
Sorry for the bad english, not my lenguage
Thanks to everybody in advance
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