- #1
kuahji
- 394
- 2
I have the data set
# of freights - probability
1 - .075
1.5 - .025
2 - .425
2.5 - .150
3 - .125
3.5 - .100
4 - .050
5 - .025
6 - .025
The question is, what is the probability that at least 5 of 6 families purchased more than four freights.
I started with making a graph of the problem & found it was skewed right. With a mean 2.537 & standard deviation 1.002. So I've ruled out using normal distribution because its skewed right. The probability of purchasing more than four freights is .025+.025=.050. But is there a way to calculated the probability that 5 of 6 families purchased more than four?
# of freights - probability
1 - .075
1.5 - .025
2 - .425
2.5 - .150
3 - .125
3.5 - .100
4 - .050
5 - .025
6 - .025
The question is, what is the probability that at least 5 of 6 families purchased more than four freights.
I started with making a graph of the problem & found it was skewed right. With a mean 2.537 & standard deviation 1.002. So I've ruled out using normal distribution because its skewed right. The probability of purchasing more than four freights is .025+.025=.050. But is there a way to calculated the probability that 5 of 6 families purchased more than four?