Tension between two sliding blocks

In summary, the problem involves two blocks of different masses and coefficients of friction connected by a cord sliding down an inclined plane. Using Newton's Laws and setting up free body diagrams, the tension in the cord can be determined to be approximately 2.722 N for an angle of 28 degrees with a calculated acceleration of 2.5 m/s^2. However, the accuracy of the solution could be improved by considering the full value of the acceleration rather than rounding it off.
  • #1
END
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Homework Statement



The problem:

gUEoZ.jpg


Two blocks made of different materials connected together by a thin cord, slide down a plane ramp inclined at an angle θ to the horizontal as shown in the figure (block B is above block A). The masses of the blocks are mA and mB and the coefficients of friction are μA and μB.

If mA=mB=5.5kg, and μA = 0.19 and μB = 0.30, determine the tension in the cord, for an angle ##θ = 28^{\circ}##

Homework Equations



Newton's Laws

The Attempt at a Solution



My Attempt:After setting up free body diagrams (not shown), I found the acceleration ##a\approx2.5~\frac{m}{s^2}## along with the following equation for T:

$$sin(\theta )mg-T-\mu _acos(\theta)mg=ma$$

$$\Rightarrow T=m(sin(\theta)g-\mu _acos(\theta)g-a)\Rightarrow$$

##T\approx 2.722 ~\textrm{N}## in magnitude

Is this the correct answer?
 
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  • #2
END said:

Homework Statement



The problem:

gUEoZ.jpg


Two blocks made of different materials connected together by a thin cord, slide down a plane ramp inclined at an angle θ to the horizontal as shown in the figure (block B is above block A). The masses of the blocks are mA and mB and the coefficients of friction are μA and μB.

If mA=mB=5.5kg, and μA = 0.19 and μB = 0.30, determine the tension in the cord, for an angle ##θ = 28^{\circ}##

Homework Equations



Newton's Laws

The Attempt at a Solution



My Attempt:


After setting up free body diagrams (not shown), I found the acceleration ##a\approx2.5~\frac{m}{s^2}## along with the following equation for T:

$$sin(\theta )mg-T-\mu _acos(\theta)mg=ma$$

$$\Rightarrow T=m(sin(\theta)g-\mu _acos(\theta)g-a)\Rightarrow$$

##T\approx 2.722 ~\textrm{N}## in magnitude

Is this the correct answer?

The solution is correct in principle, but you rounded off the acceleration too much, therefore the second digit of T is inaccurate. You could have canceled a and get T directly.

ehild
 

Related to Tension between two sliding blocks

1. What is tension between two sliding blocks?

Tension is the force that is transmitted through a string, rope, cable, or any other type of flexible connector, when it is pulled tight by forces acting from opposite ends.

2. What causes tension between two sliding blocks?

Tension between two sliding blocks is caused by the frictional forces between the two surfaces as they slide against each other.

3. How is tension between two sliding blocks calculated?

Tension can be calculated using the formula T = μN, where T is the tension force, μ is the coefficient of friction between the two surfaces, and N is the normal force acting between the blocks.

4. How does the weight of the blocks affect the tension between them?

The weight of the blocks can affect the tension between them by increasing or decreasing the normal force, which in turn affects the frictional force and therefore the tension force.

5. How does the angle of the incline affect the tension between two sliding blocks?

The angle of the incline can affect the tension between two sliding blocks by changing the normal force and therefore the frictional force acting between the two surfaces. The steeper the incline, the greater the normal force and frictional force, resulting in a higher tension force.

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