Why Does Tension Vary Along the Rope in a Hanging Superhero Scenario?

In summary: The summary is: In summary, Superhero and Trusty Sidekick are hanging motionless from a rope, with Superhero's mass being 90.0 kg, Trusty Sidekick's mass being 55.0 kg, and the mass of the rope being negligible. The free-body diagram shows Superhero being pulled down by gravity and Trusty Sidekick being pulled down by gravity, with the rope pulling up on both of them. The total tension on the rope is 1421 N, with the tension above Superhero being 1421 N minus the total weight it's being pulled down by. However, the tension between Superhero and Trusty Sidekick is only 539 N because the tension in the rope is not equal throughout
  • #1
ThePiGeek314
10
0

Homework Statement


[/B]
Superhero and Trusty Sidekick hang motionless from a rope. Superhero’s mass is 90.0 kg, while Trusty Sidekick’s is 55.0 kg, and the mass of the rope is negligible. (a) Draw a free-body diagram of the situation. (b) Find the tension in the rope above Superhero. (c) Find the tension in the rope between Superhero and Trusty Sidekick.

Homework Equations



F = ma
W = ga

The Attempt at a Solution



In the free-body diagram, I have Superhero being pulled down by gravity = 882 N, and Trusty Sidekick being pulled down by gravity = 539 N. The rope is pulling 882 N up on Superhero and 539 N up on Trusty Sidekick (definition of equilibrium, since they're motionless). I'm pretty sure the diagram is correct.

The total tension on the rope, since the mass of the rope itself is negligible = 882 + 539 = 1421 N. Because a rope pulls with equal tension on each object, the tension in the rope above Superhero is just 1421 N - the total weight it's being pulled down by.

Tension in the rope between Superhero and Trusty Sidekick should also be 1421, because tension is equal along the whole rope...but the answer is 539 N. How are the different forces at different points along the rope consistent with the tension remaining equal throughout the whole rope?
 
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  • #2
Hi Pi,
What if Sidekick let's go ? Would the tension in the lower part of the rope also be the same as in the top part ?

Can you post the free body diagram ?
 
  • #3
515960-4-34PEEI1.png
 
  • #4
ThePiGeek314 said:
That is not a free body diagram.
ThePiGeek314 said:
tension is equal along the whole rope
The fact that it is one continuous rope is confusing you. Think of it as two ropes with a join where Superhero is holding on.
Try to answer BvU's question. If Sidekick were not there, would the tension still be the same all along the rope?
 
  • #5
No, because the only weight on the rope would be Superhero's weight of 882 N. Using Newton's Third Law, the tension in the rope above Superhero would also be 882 N, right?

Using common sense, the tension in the rope below where Superhero is hanging on should be 0...but isn't tension supposed to be the same all along a rope?
 
  • #6
ThePiGeek314 said:
Nbut isn't tension supposed to be the same all along a rope?
Only if you refrain from pulling on the rope somewhere in the middle. If you've pulled on a real rope, you might notice that it is taut on one side of your hands and slack on the other.

In physics textbooks, one often uses massless, frictionless pulleys which exert zero longitudinal force along a rope. The ropes are also massless. The tension on a massless rope is indeed the same on either side of an ideal pulley. But we're not dealing with ideal pulleys here.
 

What is tension in equilibrium?

Tension in equilibrium refers to the state in which an object is being pulled or stretched evenly in all directions, resulting in a balanced and stable system. This means that all forces acting on the object are equal and opposite, resulting in no net movement.

How is tension in equilibrium calculated?

Tension in equilibrium is calculated using the formula T = F * cosθ, where T is the tension force, F is the external force acting on the object, and θ is the angle between the two forces. This calculation assumes that the object is not accelerating or rotating.

What factors affect tension in equilibrium?

The factors that affect tension in equilibrium include the magnitude and direction of the external force, the mass and shape of the object, and the angle between the external force and the object. Any changes in these factors can result in a change in tension and potentially disrupt the equilibrium of the system.

How does tension in equilibrium relate to Newton's Laws of Motion?

Tension in equilibrium is directly related to Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. In the case of tension in equilibrium, the object is being pulled in opposite directions by equal and opposite forces, resulting in a state of balance and no net movement.

What are some real-world examples of tension in equilibrium?

Some examples of tension in equilibrium include a hanging object such as a chandelier or a swing, a bridge with evenly distributed weight, and a suspended cable carrying a load. In each of these examples, the forces acting on the object are balanced, resulting in a state of tension in equilibrium.

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