- #1
smashbrohamme
- 97
- 1
A brass ring of diameter 10.00 cm at 19.9°C is heated and slipped over an aluminum rod of diameter 10.01 cm at 19.9°C. Assume the average coefficients of linear expansion are constant.
(a) To what temperature must the combination be cooled to separate the two metals?
Brass=19 x 10^-6
Aluminum=24 x 10^-6
(Change)A=γ x Ao x (change)Temperature.
This is the equation for one instance.
What is a conveniant equation to solve for both at the same time? I am stuck and I feel if I keep using that top equation I will just be guessing all day.
(a) To what temperature must the combination be cooled to separate the two metals?
Brass=19 x 10^-6
Aluminum=24 x 10^-6
(Change)A=γ x Ao x (change)Temperature.
This is the equation for one instance.
What is a conveniant equation to solve for both at the same time? I am stuck and I feel if I keep using that top equation I will just be guessing all day.