- #1
Drizzy
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Homework Statement
A referee throws a ball in a basketball game. When the ball was in his hand the heigh was 1,6 meters above the ground. The ball is caught 0.8 seconds later by a jumping player. The ball is 2.7 meters above the ground and on the way down. what was the initial velocity when the ball left the referee's hand?
Homework Equations
s=v0t + at^2/2
v=v0 + at
The Attempt at a Solution
I am guessing that the basketball player caught the ball when it was at its highest point and therefor the velocity was 0 m/s.
0 = v0 + at
at = - V0
-9,86 * 0,8 = - v=
9,82 * 0,8 = v
this answer is wrong so i tried again with the second equation and that gave the right anwer. Why is that?