- #1
GrandMaster87
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Homework Statement
Prove that
[tex]\frac{sin3x}{sinx}[/tex]-[tex]\frac{cos3x}{cosx}[/tex] = 2
Homework Equations
The Attempt at a Solution
LHS:[tex]\frac{sin(2x+x)}{sin}-\frac{cos(2x+x)}{cosx}[/tex]
=[tex]\frac{sin2x.cosx + cos2x.sinx}{sin}-\frac{cos2xcosx - sin2x.sinx}{cosx}[/tex]