Two stacked boxes and a pulley with a weight attached

That way you will be able to see how the solutions depend on the input parameters.In summary, the conversation discusses a system consisting of three masses, where mass one rests on top of mass two and the coefficient of static friction between the two masses and the table is given. The task is to find the maximum mass for M3 that will prevent mass one from sliding on mass two. The string and pulley are assumed to be massless and frictionless. The equations used to solve this problem are the equation for static friction and the sum of forces equation. It is recommended to work with variables instead of numerical values to better understand the relationship between the input parameters and the solution.
  • #1
donveppy
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Homework Statement


The system shown is released from rest. Mass one (0.450 kg) rests on mass two (0.820 kg) and the coefficient of static friction between the two masses is 0.560 and the same for the mass and the table. Determine the maximum mass for M3 such that the mass one will not slide on mass two. The string can be considered massless and the pulley is frictionless

Homework Equations


fs=uk(n)
sumF=M(a)

The Attempt at a Solution


.450(9.8)(.560)= 2.46N static friction force between block one and two

(.450+.560)(9.8)(.560)= 6.96N static friction force between both blocks stacked and table

T-(6.96N)=M(1+2)(a) sum forces x direction

w2- T=M2(a) sum forces in y direction
 
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  • #2
System shown ? Shown where ?

Oh, and: welcome to PF!

Tip: don't write calculations with numbers. Instead write expressions with variables and work with those. Only at the last step fill in values (i a numerical answer is required).
 

1. What is the purpose of the pulley in this setup?

The pulley is used to change the direction of the force applied to the weight. In this setup, the weight is attached to one end of the pulley and the rope is threaded through the pulley and attached to the other box. This allows for a downward force to be applied on one box, while an equal upward force is applied on the other box, creating a balanced system.

2. How does the weight of the pulley affect the overall system?

The weight of the pulley will affect the amount of force needed to lift the boxes. The heavier the pulley, the more force will be required to lift the boxes. Additionally, the weight of the pulley can also affect the tension in the rope and the overall stability of the system.

3. What is the relationship between the weights of the two boxes in this setup?

In this setup, the weights of the two boxes are equal. This creates a balanced system where the weight of one box is counteracted by the weight of the other box. If the weights were not equal, one box would have a greater force acting on it, causing it to move in the direction of the greater force.

4. Can the direction of the pulley affect the setup?

Yes, the direction of the pulley can affect the setup. If the pulley is placed in a different orientation, it can change the direction of the force applied to the weights. This can also affect the tension in the rope and the overall stability of the system.

5. How does friction play a role in this setup?

Friction can affect the movement of the boxes in this setup. If there is a lot of friction between the boxes and the surface they are resting on, it will require more force to move the boxes. Additionally, friction between the rope and the pulley can also affect the amount of force needed to lift the boxes.

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