U substitution and integration

In summary, the problem involves using the substitution u= x+y and v=y-2x to evaluate a double integral. The Jacobian is needed to change the limits of integration and the region of integration must be sketched in both the xy-plane and uv-plane.
  • #1
3soteric
23
0

Homework Statement



use the substitution u= x+y and v=y-2x to evaluate double integral from
∫1-0∫(1−x) -(0) of (√x+y) (y−2x)^2 dydx

Homework Equations



integration tables I am assuming

The Attempt at a Solution


i tried to integrate directly but none of my integration tables match up to the format
 
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  • #2
You should do as the assignment tells you to do.

So perform the change of variables first.
 
  • #3
I will write it in latex for those who want to solve it:
[tex]\int^{1}_{0} \int^{1-x}_{0} \sqrt{x+y} (y-2x)^2\,dy\,dx[/tex]
Also, the Jacobian of the transformation you are trying to perform is
[tex]\begin{vmatrix}
1 & 1 \\
-2 & 1
\end{vmatrix}[/tex]
What does that equal?
 
  • #4
the jacobian equals 3 but how is that related to the entire problem ? :s
 
  • #5
3soteric said:

Homework Statement



use the substitution u= x+y and v=y-2x to evaluate double integral from
∫1-0∫(1−x) -(0) of (√(x+y)) (y−2x)^2 dydx

Homework Equations



integration tables I am assuming

The Attempt at a Solution


i tried to integrate directly but none of my integration tables match up to the format

3soteric said:
the Jacobian equals 3 but how is that related to the entire problem ? :s
You need the Jacobian to change dy dx to du dv or dv du .

You will also need to change the limits of integration.

Solving the system of equations,
u= x+y

v=y-2x​

for x & y, will help you to do that.

Sketch the region of integration for the given integral, [itex]\displaystyle \int^{1}_{0} \int^{1-x}_{0} \left(\sqrt{x+y\ }\, (y-2x)^2\right)\,dy\,dx\,,\ [/itex] in the xy-plane. Then convert that to the corresponding region in the uv-plane.
 

Related to U substitution and integration

1. What is U substitution and when is it used?

U substitution is a technique used in calculus to simplify integrals that involve a composition of functions. It is typically used when the integral contains a function inside another function, such as sin(x^2) or ln(x).

2. How does U substitution work?

The basic idea of U substitution is to substitute a new variable, u, for the inner function. This new variable is then used to rewrite the integral in terms of u and its derivative, du. This often leads to a simpler integral that can be evaluated more easily.

3. What is the process for using U substitution?

The process for using U substitution involves the following steps:

  1. Identify the inner function in the integral.
  2. Choose a new variable, u, to substitute for the inner function.
  3. Find the derivative, du, of the new variable u.
  4. Substitute u and du into the integral, rewriting it in terms of u.
  5. Solve the new integral in terms of u.
  6. Substitute back in the original variable, x, to get the final answer.

4. Can U substitution be used for all integrals?

No, U substitution can only be used for certain types of integrals. It is most commonly used for integrals involving a composition of functions, but it may not be applicable for other types of integrals. It is important to consider other integration techniques, such as integration by parts, when U substitution cannot be used.

5. Are there any common mistakes when using U substitution?

Yes, there are a few common mistakes that can occur when using U substitution. These include forgetting to change the limits of integration when substituting in a new variable, not differentiating du correctly, and not substituting back in the original variable at the end. It is important to pay close attention to each step in the process to avoid these mistakes.

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