Understanding Traceless Proof for Gamma Matrices

In summary, the conversation discusses the proof of the tracelessness of gamma matrices, which is based on the identity ##\{\gamma_\mu,\gamma_\nu\} = 2\eta_{\mu\nu}## and involves moving the metric tensor ##\eta_{\mu\nu}## inside the trace due to the anti-commutation relation between the gamma matrices. The conversation also clarifies that the trace is taken over the gamma matrices, not the Lorentz indices.
  • #1
robotsheep
10
0
I'm reading through some lecture notes and there is a proof that the gamma matrices are traceless that I've never seen before (I've seen the "identity 0" on wikipedia proof) and I can't work out some of the steps:

\begin{align*}
2\eta_{\mu\nu}Tr(\gamma_\lambda) &= Tr(\{\gamma_{\mu},\gamma_{\nu}\}\gamma_\lambda)
\\ &= Tr(\gamma_\mu\gamma_\nu\gamma_\lambda + \gamma_\nu\gamma_\mu\gamma_\lambda)
\\ &= Tr(\gamma_\mu\gamma_\nu\gamma_\lambda + \gamma_\mu\gamma_\lambda\gamma_\nu)
\\ &= Tr(\gamma_\mu\{\gamma_{\nu},\gamma_{\lambda}\})
\\ &= 2\eta_{\nu\lambda}Tr(\gamma_\mu)
\\ \mu = \nu \neq \lambda \implies Tr(\gamma_\lambda) = 0
\end{align*}

In particular I don't understand the very first equality and the very last (I assume the same method is being used in both) but I understand the rest using the trace and anti commutator properties. I understand that the 2 eta factor is equal to the anti commutator but I don't see how this allows you to pull it inside of the trace, I tried to work it out explicitly using a generic 4x4 matrix for the gammas but I can't get it.

Thank you in advance for any help
 
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  • #2
The identity used is ##\{\gamma_\mu,\gamma_\nu\} = 2\eta_{\mu\nu}##. The ##2\eta_{\mu\nu}## has first been moved into the trace which is allowed since it is a number.
 
  • #3
I think I must have misunderstood something, I thought eta was a matrix?

eta=diag(-1,1,1,1)
 
  • #4
It is the metric tensor, the indices belonging to it are not the ones the trace is over.
 
  • #5
Orodruin said:
It is the metric tensor, the indices belonging to it are not the ones the trace is over.
If it's a tensor not a scalar why can we put it inside the trace? Sorry if I'm missing something obvious. I thought the indices on the eta referred to the elements in eta and the trace is the sum of the diagonal elements and so the trace would also apply to the eta?
 
  • #6
The trace is over the gamma matrices. The indices in this particular case are not summation indices and so each set of indices refer to a particular relation.
 
  • #7
I really appreciate your help, thanks for your time but I'm still struggling to understand. I understand that the indices aren't being summed over, rather that the sum of the diagonal part of the gamma matrix is the trace. I'm still not understanding why the eta matrix can be moved inside the trace as this changes it from a matrix to just a scalar once the trace is taken.
 
  • #8
For given μ and ν, the component of the metric is just a number that you can move into the trace. The anti-commutation relation between the gamma matrices allows you to exchange this number for an anti-commutator of two matrices (in the anti-commutation relation, the metric should really be multiplied by an identity matrix in the gamma matrix space). Remember that ##\gamma^\mu## for a fixed μ is a matrix, this is the matrix space you are going to take the trace in. The trace of ##\gamma^\mu## is simply ##\sum_a \gamma^\mu_{aa}## so the trace has nothing to do with the Lorentz indices.
 
  • #9
Orodruin said:
For given μ and ν, the component of the metric is just a number that you can move into the trace. The anti-commutation relation between the gamma matrices allows you to exchange this number for an anti-commutator of two matrices (in the anti-commutation relation, the metric should really be multiplied by an identity matrix in the gamma matrix space). Remember that ##\gamma^\mu## for a fixed μ is a matrix, this is the matrix space you are going to take the trace in. The trace of ##\gamma^\mu## is simply ##\sum_a \gamma^\mu_{aa}## so the trace has nothing to do with the Lorentz indices.
Thank you very much, this really clears it up for me, you've been very helpful. So just to check, on the lhs we are thinking of eta not as a whole matrix, but are instead just considering the specific components given by mu and nu?
 
  • #10
Yes. In general, in high-energy physics you will have a lot of different indices floating around, often suppressed for readability. It is important to know which indices are intended with traces, matrix multiplications, and other operations.
 
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Likes robotsheep
  • #11
Brilliant, thank you very much.
 

1. What is a Gamma matrix?

A Gamma matrix, also known as a Dirac matrix, is a mathematical object used to represent the behavior of fermions in quantum mechanics. It is a square matrix with complex elements that satisfy certain algebraic properties.

2. What does it mean for a Gamma matrix to be traceless?

A traceless Gamma matrix is one in which the sum of the elements along the main diagonal is equal to zero. This means that the matrix does not have a dominant direction or orientation, and its behavior is independent of the basis in which it is expressed.

3. How is the traceless property of Gamma matrices proven?

The traceless property of Gamma matrices can be proven using the properties of the Pauli spin matrices, which are a special case of Gamma matrices. By manipulating the algebraic equations involving the spin matrices, it can be shown that their trace is equal to zero.

4. Why is the traceless property important in quantum mechanics?

In quantum mechanics, the traceless property of Gamma matrices is important because it allows for the conservation of angular momentum. This means that the behavior of particles is not affected by the orientation of the coordinate system, making calculations and predictions easier and more accurate.

5. Are all Gamma matrices traceless?

No, not all Gamma matrices are traceless. The traceless property only holds for certain combinations of Gamma matrices, such as the Pauli spin matrices. Other combinations may have non-zero traces, but they can still be used in quantum mechanics for specific purposes.

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