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torquerotates
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Homework Statement
Toss a coin 3 times. What is the probability that we get a head on the first toss or a head on the second toss or a head on the third toss?
Homework Equations
Pr(AorB)=Pr(A)+Pr(B)-Pr(AandB)
The Attempt at a Solution
A=head on 1st toss
B=head on 2nd toss
C=head on 3rd toss
Pr(AorBorC)=Pr(A)+Pr(B)+Pr(C)-Pr(A&B&C)
=(1/2)+(1/2)+(1/2)-(1/8)=11/8
but 11/8>1 which is a contradiction. So something is wrong with my sol.