- #1
sentimentaltrooper
- 6
- 1
- Homework Statement
- A system comprising blocks, a light frictionless pulley, a frictionless incline, and connecting ropes is shown in the figure. The 9.0-kg block accelerates downward when the system is released from rest. The tension in the rope connecting the 6.0 kg block and the 4.0 kg block is closest to
- Relevant Equations
- [itex](m_2 + m_1)a - Ma = Mg - m_2 gsin\theta - m_1 gsin\theta[/itex]
To find the tension in the rope connecting 6.0 kg block and 4.0 kg block we do
6.0 kg = m1, 4.0 kg = m2, 9.0 kg = M
[itex](m_2 + m_1)a - Ma = Mg - m_2 gsin\theta - m_1 gsin\theta[/itex]
Why do we use sin in these equations and not cos?