- #1
elsternj
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Homework Statement
The base is the semicircle y = [itex]\sqrt{9-x2}[/itex](Square root of 9-x2.. i don't know why the formatting isn't showing up) where -3 <= x <= 3. The cross section perpendicular to the x-axis are squares.
Homework Equations
-3[itex]\int[/itex]3 = A(y)dy
A(y) = area of cross section
The Attempt at a Solution
Okay so i know the cross section is a square. And i see that y = [itex]\sqrt{9-x2}[/itex] creates a semi-circle. I am not sure how to find the cross sectional area. I'm assuming it needs to be in terms of y. And the area of a square is a (side)2. But how do i know what the side is equal to?