altamashghazi said:
…altamashghazi said:
altamashghazi said:
sorry wavefronts will be cylinderical out wards but i couldn't guess the pattern of change in amplitude.tiny-tim said:why??
altamashghazi said:
tiny-tim said:yes!
ok, then how is the surface area of a cylinder related to radius?
, so if you draw the field lines, they'll all be radially outward,tiny-tim said:ok
and the number going through any wavefront will be proportional to r …
so what is the loss in strength?
but its wrong the answer is a/2. therefore i m confused. pls help.tiny-tim said:yup!
thank u very mucchtiny-tim said:oh, I'm sorry, i thought a was the intensity
the intensity (as shown by field lines) is proportional to 1/r,
and the amplitude is proportional to the square-root of the intensity
tiny-tim said:oh, I'm sorry, i thought a was the intensity
the intensity (as shown by field lines) is proportional to 1/r,
and the amplitude is proportional to the square-root of the intensity
A line source is a hypothetical source of waves that extends infinitely in one dimension. It is often used in physics to simplify the analysis of wave behavior.
The amplitude of a wave from a line source is calculated using the formula A = Ar/4r, where A is the amplitude at distance r, Ar is the amplitude at the source, and r is the distance from the source.
The amplitude at distance 4r is significant because it represents the point where the wave has traveled four times the distance from the source and has spread out to form a quarter-circle. This distance is often used in calculations for wave behavior.
Yes, the amplitude at distance 4r can be negative. This means that the wave has undergone a phase shift of 180 degrees and the displacement of the wave is in the opposite direction from the source.
The amplitude decreases as the distance from the line source increases. This is due to the spreading out of the wave over a larger area as it travels further from the source.