spdowind,welcome to PF! Are you familiar with the method for calculating vector components by drawing a right triangle? Draw a sketch. The weight force acts straight down vertically...that's the hypotenuse of the right triangle. The components are the magnitudes of the legs of that right triangle, one leg parallel to the plane surface, and the other perperpendicular to it. You'll have to do a little geometry and some basic trig to calculate these components. Please show some attempt at this for further assistance.
Weight component is the amount of force exerted by an object due to its mass and the acceleration of gravity. It is a vector quantity that is typically represented by the symbol "W" and measured in Newtons (N) or pounds (lbs).
To find the force components for a box on an inclined surface, you will need to use trigonometry. The weight component of the box can be broken down into two components: the perpendicular force (normal force) and the parallel force (parallel to the surface). The normal force can be found by multiplying the weight of the box by the cosine of the angle of inclination. The parallel force can be found by multiplying the weight of the box by the sine of the angle of inclination.
The normal force is the force that a surface exerts on an object in contact with it. It is always perpendicular to the surface and acts in the opposite direction of the force that the object exerts on the surface. In the case of a box on an inclined surface, the normal force is equal to the perpendicular force component of the weight.
The parallel force is the component of a force that is parallel to a given surface. In the case of a box on an inclined surface, the parallel force is equal to the parallel force component of the weight. It is responsible for the box's motion down the incline.
The angle of inclination affects the force components by changing the ratios of the perpendicular and parallel components of the weight. As the angle increases, the parallel component increases and the perpendicular component decreases. At a 90 degree angle of inclination, the perpendicular component becomes zero and the parallel component becomes equal to the weight of the object.