What is the optimal thickness of a coating to reduce a wire's resistance by 50%?

In summary, the question asks for the thickness of a coating on a wire to reduce the resistance per unit length of the uncoated wire by 50%. This can be achieved by setting the resistance per unit length of the coated wire equal to the resistance per unit length of the uncoated wire, as the coating creates a parallel conductive path. This is represented by the equation R1 || R2 = R1R2/(R1 + R2), where R1 and R2 are the resistances of the uncoated and coated wires respectively. The combined resistance is half of the original resistance, and this can be determined by looking at the way conductive paths combine.
  • #1
Abdulwahab Hajar
56
2

Homework Statement


A long round wire of radius a and conductivity σ is coated with a material of conductivity 0.1σ. (a) What must be the thickness of the coating so that the resistance per unit length of the uncoated wire is reduced by 50%?
2. Homework Equations [/B]
R = l/(σS)
where R is the resistance, l is the length of the wire, σ the conductivity and S the cross sectional area


The Attempt at a Solution


regarding part a) the resistance per unit length of the uncoated wire is (1/σS) this equals 1/(σπa2
meaning that its resistance per unit length doesn't depend on the thickness of the coating.
However the soln manual
solved it by setting: resistance per unit length of coated wire = resistance per unit length of uncoated wire
Why is that so??
 
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  • #2
Abdulwahab Hajar said:
However the soln manual
solved it by setting: resistance per unit length of coated wire = resistance per unit length of uncoated wire
Why is that so??
The coating creates a conductive path that is parallel to the wire inside. How do parallel resistances add?
 
  • #3
gneill said:
The coating creates a conductive path that is parallel to the wire inside. How do parallel resistances add?
as follows R1 + R2 = R1R2/(R1 + R2)
 
  • #4
Abdulwahab Hajar said:
as follows R1 + R2 = R1R2/(R1 + R2)
Better written as: R1 || R2 = R1R2/(R1 + R2)

And if R1 and R2 are equal, say R1 = R2 = R, what is the combined resistance?
 
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  • #5
gneill said:
Better written as: R1 || R2 = R1R2/(R1 + R2)

And if R1 and R2 are equal, say R1 = R2 = R, what is the combined resistance?
Ok I get it, it becomes half the original
But isn't the question just asking the reduction of the resistance of the uncoated wire only whereas what you showed me would be the resistance of both.
Furthermore, how could you determine that they are in parallel??
Thank you it's much appreciated
 
  • #6
Abdulwahab Hajar said:
Ok I get it, it becomes half the original
But isn't the question just asking the reduction of the resistance of the uncoated wire only whereas what you showed me would be the resistance of both.
The question is perhaps poorly phrased, but I interpret it to mean they they want the resistance of the "new" coated wire as compared to the original uncoated wire.
Furthermore, how could you determine that they are in parallel??
Thank you it's much appreciated
Look at the way conductive paths combine. Consider a small (differential) length of the wire with the coating. The original wire will have some cross sectional area A1 while the coating will have some cross sectional area A2. Both have length dL. You could remove the coating, and form a second wire with cross section A2 in parallel with the first wire without changing the net conductivity.
 
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  • #7
gneill said:
The question is perhaps poorly phrased, but I interpret it to mean they they want the resistance of the "new" coated wire as compared to the original uncoated wire.

Look at the way conductive paths combine. Consider a small (differential) length of the wire with the coating. The original wire will have some cross sectional area A1 while the coating will have some cross sectional area A2. Both have length dL. You could remove the coating, and form a second wire with cross section A2 in parallel with the first wire without changing the net conductivity.
Thank you sir, you've been very helpful
 

1. What is the purpose of coating a wire?

The purpose of coating a wire is to protect it from external factors such as moisture, corrosion, and physical damage. Coating also helps to improve the wire's electrical conductivity and insulation properties.

2. How does the coating affect the wire's conductivity?

The coating on a wire can either increase or decrease its conductivity, depending on the type of coating material used. Some coatings, such as silver or copper, can improve the wire's conductivity, while others, such as rubber or plastic, may decrease it.

3. Can the coating on a wire wear off over time?

Yes, the coating on a wire can wear off over time due to exposure to environmental factors, such as heat, moisture, and chemicals. This can lead to a decrease in the wire's conductivity and may require re-coating or replacement of the wire.

4. Is the coating on a wire necessary for all applications?

No, the coating on a wire is not necessary for all applications. In some cases, such as in high-temperature environments, a coating may not be suitable and can even cause damage to the wire. In these cases, bare wires or specially designed coatings may be used.

5. How is the conductivity of a coated wire measured?

The conductivity of a coated wire is measured using a device called a conductivity meter. This meter measures the electrical resistance of the wire and calculates its conductivity based on its dimensions and the type of coating used. The conductivity is typically expressed in units of siemens per meter (S/m) or mhos per meter (mho/m).

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