- #1
1MileCrash
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Homework Statement
y''-2y'+2y = e^-t, y(0)=0, y'(0)=4
Homework Equations
The Attempt at a Solution
Again.. I find it to be really easy, then get it wrong. My answer is not even close. Applying the properties of the laplace transform in the usual way,
s^2L{y} - 4 - 2L{y} + 2L{y} = L{e^-t}
=>
[itex]L{y} = (\frac{1}{s+1})(\frac{1}{s^2 - 2s + 2}) + (\frac{4}{s^2-2s+2})[/itex]
Now, I split the first term into partial fractions and factored the denomenator of the second. I'll spare you all of that tedious algebra:
[itex]-\frac{1}{4}(\frac{1}{s+1}) + \frac{1}{4}(\frac{1}{s-1}) - \frac{1}{2}(\frac{1}{(s-1)^{2}}) + 4(\frac{1}{(s-1)^{2}})[/itex]The inverse laplace of that, I find to be
-(1/4)e^-t + (1/4)e^t - (1/2)te^t + 4te^t
The answer given and the one given by wolfram involves trig functions, what am I doing wrong??
Thanks!