- #1
T7
- 18
- 0
Hi,
This is undoubtedly an easy question, but I am having "one of those days"...
A fish in a pond is 2m below the water's surface. An observing eye is 0.75m above the water and a horizontal distance of 1m from the fish. Given that the water has a refractive index of 1.33, where is the image of the fish going to appear to the observer? (I am supposed to use my answer to this question to show whether or not the refractive index = real depth / apparent depth, and then state whether the position of the image changes as the observer's eye moves further away horizontally).
Without first knowing a priori where the incident ray hits the water, I'm not sure how I can diagram and calculate this one.
Any hints?
Cheers,
T7
This is undoubtedly an easy question, but I am having "one of those days"...
A fish in a pond is 2m below the water's surface. An observing eye is 0.75m above the water and a horizontal distance of 1m from the fish. Given that the water has a refractive index of 1.33, where is the image of the fish going to appear to the observer? (I am supposed to use my answer to this question to show whether or not the refractive index = real depth / apparent depth, and then state whether the position of the image changes as the observer's eye moves further away horizontally).
Without first knowing a priori where the incident ray hits the water, I'm not sure how I can diagram and calculate this one.
Any hints?
Cheers,
T7