- #1
quebecois22
- 23
- 0
Hello,
Basically, we were asked to verify the dependence of the period of an object attached on both ends by a spring upon the mass of this object in Simple Harmonic Motion. Therefore, using different masses, we calculated the period each time and made a graph where the period is a function of the root of the mass, where (2*pi)/sqrt(k) should be the slope of the line, and we had to verify the value of k obtained from that slope, to the one measured before, where we would attach the springs in a vertical manner, and hang objects and measuring the spring constant for both springs.
Now, we measured both spring constants using the latter method to be 1.81 N/m, but using all our values and the slope, we get a k value of 4.01 N/m. Now our guess was that since we had two springs, the latter is probably the sum of both springs... but why?? Are we making the right assumption?
Why, in a two spring system, should one add both spring constants when doing calculations involving k??
Thank you.. :)
Basically, we were asked to verify the dependence of the period of an object attached on both ends by a spring upon the mass of this object in Simple Harmonic Motion. Therefore, using different masses, we calculated the period each time and made a graph where the period is a function of the root of the mass, where (2*pi)/sqrt(k) should be the slope of the line, and we had to verify the value of k obtained from that slope, to the one measured before, where we would attach the springs in a vertical manner, and hang objects and measuring the spring constant for both springs.
Now, we measured both spring constants using the latter method to be 1.81 N/m, but using all our values and the slope, we get a k value of 4.01 N/m. Now our guess was that since we had two springs, the latter is probably the sum of both springs... but why?? Are we making the right assumption?
Why, in a two spring system, should one add both spring constants when doing calculations involving k??
Thank you.. :)