Write a state that will compute f=x/y^2 in maple

[CourtneyS]

Homework Statement

Using maple cw version, trying to write a state that will compute f=x/y^2 over several iterations.
y^2 is changing but x is dependent on a value input my user.
I don't really know how to write the loop?
I need the loop to run on an interval of different y values that I can put in and then the x value is determined before the loop begins and is fixed, not sure how to put that in either.

Homework Equations

f=x/y^2

The Attempt at a Solution

I guess I would have to use a do loop,
do x/y^2
and I would have to declare the x value
so x=0 for example
while y -30.5...30.5
and then answer=f; printed each time

or something like that
I'm not really sure on the syntax I haven't used maple before and the online stuff isn't very helpful.

 

[Ray Vickson]

Homework Statement

Using maple cw version, trying to write a state that will compute f=x/y^2 over several iterations.
y^2 is changing but x is dependent on a value input my user.
I don't really know how to write the loop?
I need the loop to run on an interval of different y values that I can put in and then the x value is determined before the loop begins and is fixed, not sure how to put that in either.

Homework Equations

f=x/y^2

The Attempt at a Solution

I guess I would have to use a do loop,
do x/y^2
and I would have to declare the x value
so x=0 for example
while y -30.5...30.5
and then answer=f; printed each time

or something like that
I'm not really sure on the syntax I haven't used maple before and the online stuff isn't very helpful.

I am going to try attaching a pdf file of a short Maple session that does some of what you want. I have not attached a file to a PF response before, so I don't know if it will work.

Hooray, it worked!

 

[CourtneyS]

I am going to try attaching a pdf file of a short Maple session that does some of what you want. I have not attached a file to a PF response before, so I don't know if it will work.

Hooray, it worked!

Hi!
Thanks for the reply.
I am using a different function than x/y^2 but I am getting an error even though I followed the steps you posted.
Here is my output.> Y:=seq(0+.1*(i-1),i=1..570);

Y := 0., 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2,

1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4,

2.5, 2.6, 2.7, 2.8, 2.9, 3.0, 3.1, 3.2, 3.3, 3.4, 3.5, 3.6,

3.7, 3.8, 3.9, 4.0, 4.1, 4.2, 4.3, 4.4, 4.5, 4.6, 4.7, 4.8,

4.9, 5.0, 5.1, 5.2, 5.3, 5.4, 5.5, 5.6, 5.7, 5.8, 5.9, 6.0,

6.1, 6.2, 6.3, 6.4, 6.5, 6.6, 6.7, 6.8, 6.9, 7.0, 7.1, 7.2,

7.3, 7.4, 7.5, 7.6, 7.7, 7.8, 7.9, 8.0, 8.1, 8.2, 8.3, 8.4,

8.5, 8.6, 8.7, 8.8, 8.9, 9.0, 9.1, 9.2, 9.3, 9.4, 9.5, 9.6,

9.7, 9.8, 9.9, 10.0, 10.1, 10.2, 10.3, 10.4, 10.5, 10.6, 10.7,

10.8, 10.9, 11.0, 11.1, 11.2, 11.3, 11.4, 11.5, 11.6, 11.7,

11.8, 11.9, 12.0, 12.1, 12.2, 12.3, 12.4, 12.5, 12.6, 12.7,

12.8, 12.9, 13.0, 13.1, 13.2, 13.3, 13.4, 13.5, 13.6, 13.7,

13.8, 13.9, 14.0, 14.1, 14.2, 14.3, 14.4, 14.5, 14.6, 14.7,

14.8, 14.9, 15.0, 15.1, 15.2, 15.3, 15.4, 15.5, 15.6, 15.7,

15.8, 15.9, 16.0, 16.1, 16.2, 16.3, 16.4, 16.5, 16.6, 16.7,

16.8, 16.9, 17.0, 17.1, 17.2, 17.3, 17.4, 17.5, 17.6, 17.7,

17.8, 17.9, 18.0, 18.1, 18.2, 18.3, 18.4, 18.5, 18.6, 18.7,

18.8, 18.9, 19.0, 19.1, 19.2, 19.3, 19.4, 19.5, 19.6, 19.7,

19.8, 19.9, 20.0, 20.1, 20.2, 20.3, 20.4, 20.5, 20.6, 20.7,

20.8, 20.9, 21.0, 21.1, 21.2, 21.3, 21.4, 21.5, 21.6, 21.7,

21.8, 21.9, 22.0, 22.1, 22.2, 22.3, 22.4, 22.5, 22.6, 22.7,

22.8, 22.9, 23.0, 23.1, 23.2, 23.3, 23.4, 23.5, 23.6, 23.7,

23.8, 23.9, 24.0, 24.1, 24.2, 24.3, 24.4, 24.5, 24.6, 24.7,

24.8, 24.9, 25.0, 25.1, 25.2, 25.3, 25.4, 25.5, 25.6, 25.7,

25.8, 25.9, 26.0, 26.1, 26.2, 26.3, 26.4, 26.5, 26.6, 26.7,

26.8, 26.9, 27.0, 27.1, 27.2, 27.3, 27.4, 27.5, 27.6, 27.7,

27.8, 27.9, 28.0, 28.1, 28.2, 28.3, 28.4, 28.5, 28.6, 28.7,

28.8, 28.9, 29.0, 29.1, 29.2, 29.3, 29.4, 29.5, 29.6, 29.7,

29.8, 29.9, 30.0, 30.1, 30.2, 30.3, 30.4, 30.5, 30.6, 30.7,

30.8, 30.9, 31.0, 31.1, 31.2, 31.3, 31.4, 31.5, 31.6, 31.7,

31.8, 31.9, 32.0, 32.1, 32.2, 32.3, 32.4, 32.5, 32.6, 32.7,

32.8, 32.9, 33.0, 33.1, 33.2, 33.3, 33.4, 33.5, 33.6, 33.7,

33.8, 33.9, 34.0, 34.1, 34.2, 34.3, 34.4, 34.5, 34.6, 34.7,

34.8, 34.9, 35.0, 35.1, 35.2, 35.3, 35.4, 35.5, 35.6, 35.7,

35.8, 35.9, 36.0, 36.1, 36.2, 36.3, 36.4, 36.5, 36.6, 36.7,

36.8, 36.9, 37.0, 37.1, 37.2, 37.3, 37.4, 37.5, 37.6, 37.7,

37.8, 37.9, 38.0, 38.1, 38.2, 38.3, 38.4, 38.5, 38.6, 38.7,

38.8, 38.9, 39.0, 39.1, 39.2, 39.3, 39.4, 39.5, 39.6, 39.7,

39.8, 39.9, 40.0, 40.1, 40.2, 40.3, 40.4, 40.5, 40.6, 40.7,

40.8, 40.9, 41.0, 41.1, 41.2, 41.3, 41.4, 41.5, 41.6, 41.7,

41.8, 41.9, 42.0, 42.1, 42.2, 42.3, 42.4, 42.5, 42.6, 42.7,

42.8, 42.9, 43.0, 43.1, 43.2, 43.3, 43.4, 43.5, 43.6, 43.7,

43.8, 43.9, 44.0, 44.1, 44.2, 44.3, 44.4, 44.5, 44.6, 44.7,

44.8, 44.9, 45.0, 45.1, 45.2, 45.3, 45.4, 45.5, 45.6, 45.7,

45.8, 45.9, 46.0, 46.1, 46.2, 46.3, 46.4, 46.5, 46.6, 46.7,

46.8, 46.9, 47.0, 47.1, 47.2, 47.3, 47.4, 47.5, 47.6, 47.7,

47.8, 47.9, 48.0, 48.1, 48.2, 48.3, 48.4, 48.5, 48.6, 48.7,

48.8, 48.9, 49.0, 49.1, 49.2, 49.3, 49.4, 49.5, 49.6, 49.7,

49.8, 49.9, 50.0, 50.1, 50.2, 50.3, 50.4, 50.5, 50.6, 50.7,

50.8, 50.9, 51.0, 51.1, 51.2, 51.3, 51.4, 51.5, 51.6, 51.7,

51.8, 51.9, 52.0, 52.1, 52.2, 52.3, 52.4, 52.5, 52.6, 52.7,

52.8, 52.9, 53.0, 53.1, 53.2, 53.3, 53.4, 53.5, 53.6, 53.7,

53.8, 53.9, 54.0, 54.1, 54.2, 54.3, 54.4, 54.5, 54.6, 54.7,

54.8, 54.9, 55.0, 55.1, 55.2, 55.3, 55.4, 55.5, 55.6, 55.7,

55.8, 55.9, 56.0, 56.1, 56.2, 56.3, 56.4, 56.5, 56.6, 56.7,

56.8, 56.9

> for i from 1 to 570 do
> if (i=1) then printf("%5s %5s %10s\n", "x", "y", "f(x,y)"):
> end if:
> printf("%5.1f %5.1f %10.6f\n", 2.0, Y,f(2.0,Y)):
> end do:
x y f(x,y)
2.0 0.0
Error, (in fprintf) number expected for floating point format

> i:='i';

i := i

>

 

[Mark44]

> for i from 1 to 570 do
> if (i=1) then printf("%5s %5s %10s\n", "x", "y", "f(x,y)"):
> end if:
> printf("%5.1f %5.1f %10.6f\n", 2.0, Y,f(2.0,Y)):
> end do:
x y f(x,y)
2.0 0.0
Error, (in fprintf) number expected for floating point format

You haven't defined your function. The second printf statement prints 2.0, then the value for y (0.0), and then fails to print a value for f(2.0, y).

 

[Ray Vickson]

You haven't defined your function. The second printf statement prints 2.0, then the value for y (0.0), and then fails to print a value for f(2.0, y).

Hi!
Thanks for the reply.
I am using a different function than x/y^2 but I am getting an error even though I followed the steps you posted.
Here is my output.> Y:=seq(0+.1*(i-1),i=1..570);

Y := 0., 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2,

1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4,

2.5, 2.6, 2.7, 2.8, 2.9, 3.0, 3.1, 3.2, 3.3, 3.4, 3.5, 3.6,

3.7, 3.8, 3.9, 4.0, 4.1, 4.2, 4.3, 4.4, 4.5, 4.6, 4.7, 4.8,

4.9, 5.0, 5.1, 5.2, 5.3, 5.4, 5.5, 5.6, 5.7, 5.8, 5.9, 6.0,

6.1, 6.2, 6.3, 6.4, 6.5, 6.6, 6.7, 6.8, 6.9, 7.0, 7.1, 7.2,

7.3, 7.4, 7.5, 7.6, 7.7, 7.8, 7.9, 8.0, 8.1, 8.2, 8.3, 8.4,

8.5, 8.6, 8.7, 8.8, 8.9, 9.0, 9.1, 9.2, 9.3, 9.4, 9.5, 9.6,

9.7, 9.8, 9.9, 10.0, 10.1, 10.2, 10.3, 10.4, 10.5, 10.6, 10.7,

10.8, 10.9, 11.0, 11.1, 11.2, 11.3, 11.4, 11.5, 11.6, 11.7,

11.8, 11.9, 12.0, 12.1, 12.2, 12.3, 12.4, 12.5, 12.6, 12.7,

12.8, 12.9, 13.0, 13.1, 13.2, 13.3, 13.4, 13.5, 13.6, 13.7,

13.8, 13.9, 14.0, 14.1, 14.2, 14.3, 14.4, 14.5, 14.6, 14.7,

14.8, 14.9, 15.0, 15.1, 15.2, 15.3, 15.4, 15.5, 15.6, 15.7,

15.8, 15.9, 16.0, 16.1, 16.2, 16.3, 16.4, 16.5, 16.6, 16.7,

16.8, 16.9, 17.0, 17.1, 17.2, 17.3, 17.4, 17.5, 17.6, 17.7,

17.8, 17.9, 18.0, 18.1, 18.2, 18.3, 18.4, 18.5, 18.6, 18.7,

18.8, 18.9, 19.0, 19.1, 19.2, 19.3, 19.4, 19.5, 19.6, 19.7,

19.8, 19.9, 20.0, 20.1, 20.2, 20.3, 20.4, 20.5, 20.6, 20.7,

20.8, 20.9, 21.0, 21.1, 21.2, 21.3, 21.4, 21.5, 21.6, 21.7,

21.8, 21.9, 22.0, 22.1, 22.2, 22.3, 22.4, 22.5, 22.6, 22.7,

22.8, 22.9, 23.0, 23.1, 23.2, 23.3, 23.4, 23.5, 23.6, 23.7,

23.8, 23.9, 24.0, 24.1, 24.2, 24.3, 24.4, 24.5, 24.6, 24.7,

24.8, 24.9, 25.0, 25.1, 25.2, 25.3, 25.4, 25.5, 25.6, 25.7,

25.8, 25.9, 26.0, 26.1, 26.2, 26.3, 26.4, 26.5, 26.6, 26.7,

26.8, 26.9, 27.0, 27.1, 27.2, 27.3, 27.4, 27.5, 27.6, 27.7,

27.8, 27.9, 28.0, 28.1, 28.2, 28.3, 28.4, 28.5, 28.6, 28.7,

28.8, 28.9, 29.0, 29.1, 29.2, 29.3, 29.4, 29.5, 29.6, 29.7,

29.8, 29.9, 30.0, 30.1, 30.2, 30.3, 30.4, 30.5, 30.6, 30.7,

30.8, 30.9, 31.0, 31.1, 31.2, 31.3, 31.4, 31.5, 31.6, 31.7,

31.8, 31.9, 32.0, 32.1, 32.2, 32.3, 32.4, 32.5, 32.6, 32.7,

32.8, 32.9, 33.0, 33.1, 33.2, 33.3, 33.4, 33.5, 33.6, 33.7,

33.8, 33.9, 34.0, 34.1, 34.2, 34.3, 34.4, 34.5, 34.6, 34.7,

34.8, 34.9, 35.0, 35.1, 35.2, 35.3, 35.4, 35.5, 35.6, 35.7,

35.8, 35.9, 36.0, 36.1, 36.2, 36.3, 36.4, 36.5, 36.6, 36.7,

36.8, 36.9, 37.0, 37.1, 37.2, 37.3, 37.4, 37.5, 37.6, 37.7,

37.8, 37.9, 38.0, 38.1, 38.2, 38.3, 38.4, 38.5, 38.6, 38.7,

38.8, 38.9, 39.0, 39.1, 39.2, 39.3, 39.4, 39.5, 39.6, 39.7,

39.8, 39.9, 40.0, 40.1, 40.2, 40.3, 40.4, 40.5, 40.6, 40.7,

40.8, 40.9, 41.0, 41.1, 41.2, 41.3, 41.4, 41.5, 41.6, 41.7,

41.8, 41.9, 42.0, 42.1, 42.2, 42.3, 42.4, 42.5, 42.6, 42.7,

42.8, 42.9, 43.0, 43.1, 43.2, 43.3, 43.4, 43.5, 43.6, 43.7,

43.8, 43.9, 44.0, 44.1, 44.2, 44.3, 44.4, 44.5, 44.6, 44.7,

44.8, 44.9, 45.0, 45.1, 45.2, 45.3, 45.4, 45.5, 45.6, 45.7,

45.8, 45.9, 46.0, 46.1, 46.2, 46.3, 46.4, 46.5, 46.6, 46.7,

46.8, 46.9, 47.0, 47.1, 47.2, 47.3, 47.4, 47.5, 47.6, 47.7,

47.8, 47.9, 48.0, 48.1, 48.2, 48.3, 48.4, 48.5, 48.6, 48.7,

48.8, 48.9, 49.0, 49.1, 49.2, 49.3, 49.4, 49.5, 49.6, 49.7,

49.8, 49.9, 50.0, 50.1, 50.2, 50.3, 50.4, 50.5, 50.6, 50.7,

50.8, 50.9, 51.0, 51.1, 51.2, 51.3, 51.4, 51.5, 51.6, 51.7,

51.8, 51.9, 52.0, 52.1, 52.2, 52.3, 52.4, 52.5, 52.6, 52.7,

52.8, 52.9, 53.0, 53.1, 53.2, 53.3, 53.4, 53.5, 53.6, 53.7,

53.8, 53.9, 54.0, 54.1, 54.2, 54.3, 54.4, 54.5, 54.6, 54.7,

54.8, 54.9, 55.0, 55.1, 55.2, 55.3, 55.4, 55.5, 55.6, 55.7,

55.8, 55.9, 56.0, 56.1, 56.2, 56.3, 56.4, 56.5, 56.6, 56.7,

56.8, 56.9

> for i from 1 to 570 do
> if (i=1) then printf("%5s %5s %10s\n", "x", "y", "f(x,y)"):
> end if:
> printf("%5.1f %5.1f %10.6f\n", 2.0, Y,f(2.0,Y)):
> end do:
x y f(x,y)
2.0 0.0
Error, (in fprintf) number expected for floating point format

> i:='i';

i := i

>

Look again at your printf statement, and compare it (very carefully) with what I wrote in my little worksheet. See the difference?

Note: I have tried several time, unsuccessfully, to write exactly what you should do, but for reasons I do not understand the PF server changes my message and refuses to print what I submitted. Therefore, I cannot tell you in detail what the problem is! I can try to sneak around the problem however: Y is an array and can only have a singe (first) element printed. What you want to do is compute and print the single value Y-of-i, etc. (The PF server will not even let me put Y-of-i in symbol form!)

 

[Ray Vickson]

You haven't defined your function. The second printf statement prints 2.0, then the value for y (0.0), and then fails to print a value for f(2.0, y).

In addition to the difficulty outlined in my previous response, the PF system also had me responding to you instead of the OP!

 

[Mark44]

Look again at your printf statement, and compare it (very carefully) with what I wrote in my little worksheet. See the difference?

Note: I have tried several time, unsuccessfully, to write exactly what you should do, but for reasons I do not understand the PF server changes my message and refuses to print what I submitted. Therefore, I cannot tell you in detail what the problem is! I can try to sneak around the problem however: Y is an array and can only have a singe (first) element printed. What you want to do is compute and print the single value Y-of-i, etc. (The PF server will not even let me put Y-of-i in symbol form!)

The problem is in the bracket notation for arrays. You can write Y[j] but doing so with an index of i, the system thinks you are writing the start tag for italics. Change the index to j or some variable other than i and it will work for you.

 

[CourtneyS]

You haven't defined your function. The second printf statement prints 2.0, then the value for y (0.0), and then fails to print a value for f(2.0, y).

I did it's just above. I didn't include that part of the output because I know I have that done right.

 

[Mark44]

Try this, which is similar to what Ray was trying to convey:

for j from 1 to 570 do
> if (j=1) then printf("%5s %5s %10s\n", "x", "y", "f(x,y)"):
> end if:
> printf("%5.1f %5.1f %10.6f\n", 2.0, Y[j],f(2.0,Y[j])):
>end do:

Note that I changed the loop variable from i to j, because of the way that i inside brackets is displayed here at PF (i.e., as italic). You don't need to change i.
Also note that in the second printf statement I have Y[j] in two places instead of just Y. The difference is that Y represents the whole array in some form, but what you want is a specific element in the array.

One other thing. I don't know Maple at all, but if it is anything like C or C++, there's a difference between the = and == operators. The = operator is used for assignment and the == operator is used to determine whether two expressions have the same value. Your 'if (x = 1)' might not be doing what you want it to.

 

[CourtneyS]

Try this, which is similar to what Ray was trying to convey:

for j from 1 to 570 do
> if (j=1) then printf("%5s %5s %10s\n", "x", "y", "f(x,y)"):
> end if:
> printf("%5.1f %5.1f %10.6f\n", 2.0, Y[j],f(2.0,Y[j])):
>end do:

Note that I changed the loop variable from i to j, because of the way that i inside brackets is displayed here at PF (i.e., as italic). You don't need to change i.
Also note that in the second printf statement I have Y[j] in two places instead of just Y. The difference is that Y represents the whole array in some form, but what you want is a specific element in the array.

One other thing. I don't know Maple at all, but if it is anything like C or C++, there's a difference between the = and == operators. The = operator is used for assignment and the == operator is used to determine whether two expressions have the same value. Your 'if (x = 1)' might not be doing what you want it to.

Hi,
If I use this I get error unexpected /
If take the / out it gives the error, error missing operator or ';'

 

[Mark44]

Hi,
If I use this I get error unexpected /
If take the / out it gives the error, error missing operator or ';'

Where is there a /? I don't see one at all in the code I provided.

 

[CourtneyS]

Hi,
If I use this I get error unexpected /
If take the / out it gives the error, error missing operator or ';'

I got it to work thanks!

 

[CourtneyS]

In addition to the difficulty outlined in my previous response, the PF system also had me responding to you instead of the OP!

I got it to work thanks!

 

[Ray Vickson]

The problem is in the bracket notation for arrays. You can write Y[j] but doing so with an index of i, the system thinks you are writing the start tag for italics. Change the index to j or some variable other than i and it will work for you.

That is good to know. Thanks.

 

[Ray Vickson]

Try this, which is similar to what Ray was trying to convey:

for j from 1 to 570 do
> if (j=1) then printf("%5s %5s %10s\n", "x", "y", "f(x,y)"):
> end if:
> printf("%5.1f %5.1f %10.6f\n", 2.0, Y[j],f(2.0,Y[j])):
>end do:

Note that I changed the loop variable from i to j, because of the way that i inside brackets is displayed here at PF (i.e., as italic). You don't need to change i.
Also note that in the second printf statement I have Y[j] in two places instead of just Y. The difference is that Y represents the whole array in some form, but what you want is a specific element in the array.

One other thing. I don't know Maple at all, but if it is anything like C or C++, there's a difference between the = and == operators. The = operator is used for assignment and the == operator is used to determine whether two expressions have the same value. Your 'if (x = 1)' might not be doing what you want it to.

In Maple, ":=" is the assignment operation, while "=" is either a binary relationship or the signal for an equation, depending on context.
For example:
x:=2;
x := 2
is(x=2): lprint(%);
true
> is(x=1): lprint(%);
false
> eq:=y^2=z: lprint(%);
y^2 = z
> solve(eq,y): lprint(%);
z^(1/2), -z^(1/2)

 

[CourtneyS]

In Maple, ":=" is the assignment operation, while "=" is either a binary relationship or the signal for an equation, depending on context.
For example:
x:=2;
x := 2
is(x=2): lprint(%);
true
> is(x=1): lprint(%);
false
> eq:=y^2=z: lprint(%);
y^2 = z
> solve(eq,y): lprint(%);
z^(1/2), -z^(1/2)

Hi,
If I put in a negative x co-ordinate the it doesn't give me the right output.
Any ideas on how to fix this?

 

[Ray Vickson]

Hi,
If I put in a negative x co-ordinate the it doesn't give me the right output.
Any ideas on how to fix this?

I cannot figure out exactly what your problem is because you have not given us a formula for your function. You must supply more details.

 

[CourtneyS]

I cannot figure out exactly what your problem is because you have not given us a formula for your function. You must supply more details.

The formula for the function is arctan((1.82+x)/y) - arctan(x/y)

 

[Ray Vickson]

The formula for the function is arctan((1.82+x)/y) - arctan(x/y)

So, this is related to the "skater" problem you described in another thread (provided that the goal is along the x-axis and the skater travels parallel to the y-axis). If x < 0 the skate-line goes through the inside of the goal, so the two angles add instead of subtract. This is also reflected in your formula, because -arctan(x/y) > 0. What is wrong with that?

 

[Mark44]

Hi,
If I put in a negative x co-ordinate the it doesn't give me the right output.
Any ideas on how to fix this?

If you put in a negative x coordinate for what? Please show us the Maple code that you're talking about.

 

[CourtneyS]

So, this is related to the "skater" problem you described in another thread (provided that the goal is along the x-axis and the skater travels parallel to the y-axis). If x < 0 the skate-line goes through the inside of the goal, so the two angles add instead of subtract. This is also reflected in your formula, because -arctan(x/y) < 0. What is wrong with that?

Can I just say that the angle for x=-1 is the same for x=1 because they're the same position just on the opposite side?
Would that be true?
I guess I could incorporate a shift so that my x=0 was on the far left of the rink but I have already done a lot of calculations and would rather not start over.

 

[Ray Vickson]

Can I just say that the angle for x=-1 is the same for x=1 because they're the same position just on the opposite side?
Would that be true?
I guess I could incorporate a shift so that my x=0 was on the far left of the rink but I have already done a lot of calculations and would rather not start over.

No, you cannot claim that the angle for x = -1 is the same as for x = 1, because your x = distance past the right-hand end of the goal. The point x = 1 is at a distance of 1.91 from the center of the goal, while x = -1 is at a distance of -0.09 from the center of the goal. With your choice of variables, the goal's center is at x = -0.91.

 

[CourtneyS]

No, you cannot claim that the angle for x = -1 is the same as for x = 1, because your x = distance past the right-hand end of the goal. The point x = 1 is at a distance of 1.91 from the center of the goal, while x = -1 is at a distance of -0.09 from the center of the goal. With your choice of variables, the goal's center is at x = -0.91.

I chose (0,0) as the middle of the goal line. Is my equation wrong for this?

 

[CourtneyS]

I chose (0,0) as the middle of the goal line. Is my equation wrong for this?

Please respond via dm if you can.

 

[Ray Vickson]

I chose (0,0) as the middle of the goal line. Is my equation wrong for this?

Please repeat the equation. The one you wrote before does not seem to fit this new definition of x.