Young's double slit experiment: Determine thickness of mica

In summary, the question is asking for the exact thickness of a sheet of mica that is covering one slit of a double-slit apparatus and has a refractive index of 1.582. The central maximum of 539 nm is given and the question implies that the central peak is still central for light of this wavelength. This means that the change in optical path when the mica is added is an integral number of wavelengths. The optical path in air is equal to the distance, while the optical path in the mica is equal to n times the distance. Therefore, to solve for the thickness of the mica, the optical path in the mica must be found.
  • #1
DriesBoon
2
0

Homework Statement


A sheet of mica ( approximate 6-7 µm) covers one slit
of a double-slit apparatus and has a n= 1.582. There is a central maximum of 539 nm. What is the exact thickness of the sheet of mica?

Homework Equations

The Attempt at a Solution


I think you can solve this with the number of wavelengths that go throug the sheet? But I'm a but stuck on the question.
 
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  • #2
Welcome to the forum.

It seems like the question is implying that the central peak is still central for light of wavelength 539 nm. So the change in optical path when putting the mica on one side is an integral number of wavelengths. The optical path in air (treated as n=1, the n of air is something like 1.0003) is just the distance. The optical path in the mica with n>1 is n * the distance.

Is that enough of a hint?
 
  • #3
So, I need to find the opitcal path in the mica? Wich is n times the distance of air? I understand i correctly
 

1. What is the Young's double slit experiment?

The Young's double slit experiment is a classic experiment in optics that demonstrates the wave nature of light. It involves shining a beam of light through two narrow slits and observing the resulting interference pattern.

2. How is the thickness of mica determined in this experiment?

The thickness of mica is determined by measuring the distance between the slits and the interference pattern on a screen. By using the known wavelength of light and the distance between the slits, the thickness of mica can be calculated using the equation for constructive interference.

3. What is the significance of the interference pattern in this experiment?

The interference pattern observed in the Young's double slit experiment is significant because it demonstrates the wave nature of light. The pattern is created by the interference of two separate waves, proving that light behaves like a wave.

4. What factors can affect the accuracy of the experiment?

The accuracy of the experiment can be affected by factors such as the distance between the slits, the wavelength of light used, and the quality of the mica sample. Any slight variations in these factors can result in a different interference pattern and potentially affect the accuracy of the measurement.

5. How has the Young's double slit experiment been used in other areas of science?

The principles of the Young's double slit experiment have been applied in various areas of science, including quantum mechanics, nanotechnology, and astronomy. It has also been used to study the properties of other wave-like phenomena, such as sound and water waves.

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