pmb_phy said:
All this is a very terrible interpretation of the facts. If the photon is emitted *at* the event horrizon then it can't escape from the horizon and therefore nobody will measure the photon's energy at all since you'd have to have an instrument sitting at rest at the event horizon and that is impossible.
Yep. You would think that when amateurs arrive at an apparent contradiction in a subject they havaen't studied much, that they would stop and think that perhaps it is their understanding at fault.
I think most people, in fact, do exercise such caution. I'm not quite sure what motivates people to attack science and relativity based on their own misunderstandings, but I've seen a lot of it.
The path that a photon would take if it were emitted exactly at the event horion would be to "hang there" (at the event horizon) in Schwarzschild coordinates.
It would be possible for someone else who was falling through the black hole to encounter that photon - but it would not be possible for anyone outside the event horizon to encounter it.
The easiest experiment to imagine would be that someone was falling into a black hole on a longish space-ship. Right when the nose of the space-ship is calculated to enter the event horizon, the nose of the spaceship emits a pulse of light.
A receiver at the back of the space-ship would receive the light normally a short time later. The frequency of the light would be essentialy the same as the emitted light (tidal forces would cause a very small redshift).
This follows from the fact that nothing particularly special happens at the event horizon of a large black hole (other than normal tidal forces due to any large mass) from the viewpoint of someone unfortunate enough to be falling into it. The part that hurts is when they inevitably encounter the singularity at the center a short time later, and are torn apart by tidal forces.
But the energy of a photon
will not change as it moves through a gravitational field, neither will its frequency. That too is a misconception. The only thing that will change is when the light energy is measured locally at different places. Okun et al wrote an article on this as did I (my website is not being nice now since I was unable to locate my web page on this.)
See
On the Interpretation of the Redshift in a Static Gravitational Field, L.B. Okun, K.G. Selivanov, V.L. Telegdi, Am.J.Phys. 68 (2000) 115
This is online at -
http://xxx.lanl.gov/abs/physics/9907017
Pete
You are arguing philosophy again. These poor people are already confused enough, you don't need to confuse them more by providing alternative philosophical approaches to the explanation of gravitational redshift/blueshift.
Consider what they've gotten wrong already, and imagine the probability of them correctly understanding what you are saying.
If you _still_ must arge philosphy, please provide an actual experiment to argue about, arguing about vague things like whether a photon does or does not change energy doesn't make sense unless one specifies how the photon's energy is measured.
If we take the "Harvard tower" experiment as an example, where we have a Mossenbauer x-ray of a very well defined frequency emitted at the top of a tower, we can say that the Mossenbauer receiver (which is of necessity tuned to the exact same frequency as the transmitter, in the sense that the frequency cannot be adjusted) will NOT detect the photon emitted at the top of the tower.
While philosophically one can argue about wheter it is the photon that has changed (gravitational blueshift), or the reciever that has changed (gravitational time dilation), it is quite clear that one of them has changed.
Basically, it's a matter of personal preference to say which one has changed. It's important to be consistent about the issue in the approach one takes, but either approach works.