Recent content by 8parks11

  1. 8

    340 Hz note is played outdoors. Temperature and wave length

    yes I figured this out. Sorry for not reposting. I found the velocity of sound at room temperature which is approximately 340.
  2. 8

    How to Solve a Work and Force Problem with Constant Velocity and Friction

    so you know a). for b),c) and d) just draw a FBD for each. hint: d) should be just mg.
  3. 8

    Coefficient of Friction of a olympic skier

    hmm i kept thinking that this problem was to find time! I believe u need the mass to find the friction force.
  4. 8

    Coefficient of Friction of a olympic skier

    think of it this way. The skier skied down with velocity 20 m/s and 30 degrees downwards stopped (or is in rest) in distance 145 meters. would the mass of the skier be really necessary?
  5. 8

    Coefficient of Friction of a olympic skier

    think of the equation that does not require mass. (or it might cancel out!)
  6. 8

    340 Hz note is played outdoors. Temperature and wave length

    Homework Statement A 340 Hz note is played outdoors on a day when the temperature is 25 degrees Celcius. What is the closest estimate of the wavelength of this note? A) .1 m B) 1 m C) 10 m D) 50 m E) 340 m Homework Equations...
  7. 8

    Calculating Force Between Two Conducting Spheres

    thanks for the great explanation. the directions are just attractice and repulsive respectively.
  8. 8

    Calculating Force Between Two Conducting Spheres

    any help. i still can';t figure this basic problem out
  9. 8

    Calculating Force Between Two Conducting Spheres

    Homework Statement Two conducting spheres of the same size have charges q1=-4x10^-6 and q2 = 8x10^-6C,and their centers are separated by 3.0cm a) what is the force between them? b) what would be the force if the spheres were touched together and again separated by the same distance...
  10. 8

    Projecticle Motion: Clay or Rubber Ball?

    to make it more explicit P2-P1 becomes P2-(-P1) for the rubber ball and P2+P1 so it will have be much higher.
  11. 8

    Projecticle Motion: Clay or Rubber Ball?

    meh i got it so the rubber ball will have a negative velocity while the clay will have equal velocity with the door.
  12. 8

    Projecticle Motion: Clay or Rubber Ball?

    J = FΔt, J = mΔv J = P2 - P1 the ones I used/need to know i guess... anyways I am interested in only the first part. we are interested in the change of momentum. so p2-p1 is higher for the clay because it sticks -> higher t.
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    Projecticle Motion: Clay or Rubber Ball?

    so the answer is the clay because it has a higher T value = higher momentum?
  14. 8

    Projecticle Motion: Clay or Rubber Ball?

    impulse = F x T and since they both have equal mass it doesn't matter except the clay has a larger T value (since it sticks) so the impulse is larger? not sure
  15. 8

    Projecticle Motion: Clay or Rubber Ball?

    You want to close an open door by throwing either a 400-g lump of clay or a 400-g rubber ball toward it. You can throw either object with the same speed, but they are different in that the rubber ball bounces off the door while the clay just sticks to the door. Which projectile will apply the...
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