Recent content by _Greg_

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    Calculating K Values (VLE Coefficients)

    Thanks Vulgar Just wasn't sure because there's different forms of the antoine equation, some say Psat, other just say P. Could have done this like 2 years ago, now in my final year I struggle with some of the basics lol. Cheers for clearing that up ;)
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    Calculating K Values (VLE Coefficients)

    Right so basically, I'm doing a multicomponent distillation with some exotic chemicals. My feed comes in at 13kPa and 60*C, so it's under vaccum. This will be a two phase mixture. What I need is the vapour-liquid-equilibrium coefficients, 'K- values' at feed conditions. I'm basing this on an...
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    How Can I Design a Solvent Recovery Column for MIBK and Acrylic Acid Separation?

    Please, anyone, I seriously feel like dropping out at this rate :(
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    How Can I Design a Solvent Recovery Column for MIBK and Acrylic Acid Separation?

    Hi folks I'm currently in my last year of my chemical engineering degree and doing a design project on the manufacture of acrylic acid. I have the job of designing a solvent recovery column, where a mixture of Methylisobutylketone (MIBK) solvent (heavy key) and acrylic acid (light key) are...
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    Laplace transform into partial fractions, then I'm stuck

    oh yea, woops The question is: obtain the process response Y(t) as deviation from its initial steady state condition y(0). Use Laplace transforms and expansion by partial fractions. Assume a unit step forcing function x(t) = u(t) The initial equation is 9y''(t) + 9y'(t) +4y(t) = 8x(t) - 4
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    Laplace transform into partial fractions, then I'm stuck

    -4.5 * 2 = -8 -4.5 * 0.441i = 1.9845i 3.969i * 2 = 7.938i 3.969i * 0.441i = 1.75i just used that 'foil' method
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    Laplace transform into partial fractions, then I'm stuck

    I kinda get you, see if this is right: 8 ----------------------- 9(-0.5+0.441i)(2*0.441i) 8 ----------------------- (-4.5+3.969i)(2*0.441i) 8 ------------------------- -8 -1.9845i + 7.938i +1.75i 8 --------------- -8 +...
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    Laplace transform into partial fractions, then I'm stuck

    How did you simplify the bottom line down to -3.50066 - 3.969i ? What do you do with the 9? I find it confusing because its (...+...)(...x...) not ++ or xx My basic maths has left me lol. Thanks
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    Laplace transform into partial fractions, then I'm stuck

    Homework Statement It's hard to explain, I can do everything exept get the answer to what I'v pointed out below. I just don't know what order to solve it into get the correct answer, I must have tried every method except the right one! Homework Equations The Attempt at a...
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    Shear Thickening Fluid Armour - Poject Idea

    Thanks for the input Smith and everyoe else. Unfortunately I never got the go-adead for this project as my tutor thought it would be too difficult and time consuming, plus they were meant to observe my work in college. I ended up doing HPLC analysis on various different types of chocolate (for...
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    Linear approximations derived from Taylor series

    aaaaaaah, I see, I thought that little n symbol was pi. And of course, it all adds up to 180*, high school maths is all coming back now :rolleyes: Many thanks :smile:
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    Linear approximations derived from Taylor series

    Thanks for the fast reply tiny tim. But how would you know its a 30* triangle, and how do you know cos pi/6 = sqrt3/2 Like sin pi/6, is pi close enough to 3 to just call it 3/6? I don't really know much of the basics, I'm pretty much learning this for the deep end, looking for trends to...
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    Linear approximations derived from Taylor series

    Homework Statement So I have the problem questiona dn my teachers solution posted below. I understand: f(xo) = sin pi/6 f '(xo) = cos pi/6 but i don't know how he gets them into fraction form with the SQRT of 3, it looks like some pythagoras but i don't really know how he did it...
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    Particular Integral - Help equating terms

    Cheers Pengwuino, I think I get the general idea, so separate t2 values from t's then everything else, so: 2A - (2At + B) - 2(At2 + Bt + C) = t2 Breaking down brackets: 2A - 2At - B -2At2 - 2Bt - 2C = t2 (-2A)t2 + (-2A -2B)t + (2A - B - 2C) = 1 + 0 + 0 Therefore: (-2A) = 1...
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    Particular Integral - Help equating terms

    Homework Statement Ok, so I have a 2nd order differential equation, I can get the complimentary function no problem, its getting numerical values for terms in the particular integral that I can't do. Homework Equations y'' - y' - 2y = t2 The Attempt at a Solution...
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