Recent content by a13x

I have included a diagram from the question regarding the section. For the first part the column is fixed-free Second part it is Fixed-Pinned There is no safety factor given in the question. Apart from what I have done myself shown in first post I'm totally stuck with it. All information I...

Homework Statement This seems to a reasonably basic question to go through but yet I seem to have a bit of a mental block on it. so any help in the right direction would be great.. An I-beam is 10mm thick on the web and flange, is 6m high and has a Young's modulus of 200 GN/m2. The design must...

Can definitely see where I went wrong with this. Didn't assume the pressure was the outside pressure. Thanks for the help. made things seem a lot simpler.

For this I got: 1/2 u^2+P/ρ+gh=constant the constant being wind tunnel pressure of 100Kpa. Ended up with u = 3.963 m/s

Got it now. Energy in and out have to be equal. With the energy in being 200J, the same has to be said or energy out. Ti = To = 200. Just have to convert the equation so Ti is the unknown. Thanks for the help guys

I know some of the energy used will be converted to heat and noise but can't seem to find an equation to work it out. I think the indoor temperature will be the initial 25^oC plus however much heat is given off by the fan. Not sure if I am correct in this assumption or not.

room temperatures, please help! Homework Statement A room is initially at the outdoor temperature of 25C. Now a large fan that consumes 200W of electricity when running is turned on. The heat transfer rate between the room and the outdoor air is given as Q = UA(Ti - To) where U = 6 W/m^2^.oC...

Sorry, I did mean 8J/s. Thankyou for the reply

Homework Statement Been at this question for some time an needing a double check to see if things are right. A fan that consumes 20W of eletric power when operating is claimed to discharge air from a ventilaed room at a rate of 0.25 kg/s at a discharge velocity of 8 m/s. Determine if this...