Recent content by Aaron Curran

The problem reads: "You are given a string of fixed length l with one end fastened at the origin O, and you are to place the string in the (x, y) plane with its other end on the x-axis in such a way as to maximise the area between the string and the x axis. Show that the required shape is a...

It was a typo haha, I've worked it out now anyway, feel very stupid for making this thread :sorry:

Never mind, I figured it out!

I know that if it were 1/(v2+4) then it would be ln(v2+4) but the other v in the numberator is throwing me off, any help would be much appreciated!

Okay, so I'm currently sitting my final exams before I'll be attending university come September. Here in Ireland if you wish to attend any third level institute then you must apply to CAO (Central Applications Office) on your CAO application you put a numbered list of courses you are interested...

Could you elaborate on this a bit? Not quite sure what you mean..

Yes I realized this after I posted, I'll try that, thanks!

Here is the problem (Q3 (A)); Here's what I have so far; Any help would be appreciated, thank you!

I thought about that but then I thought it was too simple, thanks so much for all your help! It seems so simple now that I know, makes me feel stupid for not seeing it earlier lol, thanks again!

Yeah that's what I meant, I should have expressed it as N33.56E, I get where you're coming from but I still don't know how to go about calculating it

I want to say 90-33.56 but I have a feeling that is wrong, other than that I really don't know

is E33.56N one of them?

Yes, i see, well how do I go about calculating the direction is v=6

by intercept in the question I think they mean when ship B crosses the path which ship A is taking, in the case of a collision or going to take in the case of an interception? because 2.(b)(ii) asks that if v=6 show that B can travel in either of two directions to intercept A and find these...

Think I have it, the minimum value of the j (verticle/y component) is 5j (5km/h) and if the value of V=6 then the directions of interception are due north and N6.59degreesW