Recent content by AbhinavJ

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    Pseudo forces and negative acceleration

    Yes! If a and a0 are in the same direction, and we assumed that they are opposite in direction one of them would come out to be negative and correct us. Just put in the signs of the forces correctly.
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    W=(1/2)KA^2 Can someone explain this equation in detail & Q

    Well, whatever force we apply on the spring to contract it is stored in the spring as its potential energy. So the work done in compressing the spring is F.x. Where x is the compression in the spring. As the force varies with the compression(kx) here we calculate the work done for elemenal...
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    W=(1/2)KA^2 Can someone explain this equation in detail & Q

    Try to derive it yourself. Ill give you a hint. Restoring force applied by a spring is directly proportional to its contraction/expansion in the direction to attain natural length. F=-Kx, also work done is F. dx. Try getting an answer
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    Pseudo forces and negative acceleration

    Here we have just assumed a>a0. If our assumption is wrong, the acceleration will become negative and tell us that our assumption is opposite to what actually is happening. You can assume m3 to be accelerating upwards, you will get the same answer but with different signs.
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    Find current induced in the photoelectric effect

    Are you sure? What is the energy of a photon dependant on?
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    Work done by a 20% efficient heat engine

    The fire was the hot reservoir
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    Work done by a 20% efficient heat engine

    Every engine has a working fluid inside it which is responsible for all the things the engine does. It is the fluid which absorbs heat from the hot reservoir and also the one to reject heat into the cold reservoir. Let's talk about the basic heat engine, A Steam engine. Water here is the...
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    Work done by a 20% efficient heat engine

    The heat given by the hot reservoir is equal to the heat taken by the engine. Glad you found your mistake, does your answer match now?
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    Velocity of efflux out of a water tank

    Wow, I am a lucky guy :p
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    Work done by a 20% efficient heat engine

    Okay, so isn't the heat taken by the engine equal to the heat rejected by the reservoir? Consider your attached file, is their any other way that the heat is being dissipated or lost other than being absorbed by the engine?
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    Work done by a 20% efficient heat engine

    What do you mean by Qh and Qc?
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    Work done by a 20% efficient heat engine

    Your professor is absolutely correct. See, how a heat engine works is that it absorbs heat from the hot reservoir, uses part of it to do some work and rejects the remaining heat to the cold reservoir...
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    Work done by a 20% efficient heat engine

    By Qc = 500 you imply that the Work done by the engine is 0. I can't see it being right. Can you show how you got it to be 500? P. S The wording seems more than fine to me
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