Recent content by Airp

Thank You!

Homework Statement how far from the rim of a disk of Radius R must the pivot point be located in order for its period of oscillation to be a minmum where R is the distance from the point to the centre of mass? I'm stuck at the derivative because I saw a similar problem where the answer is...

Oh, I actually found the solution... You have to add the X's which equal to one. With the system of equation you can substitute and only then you only have one unknown! (Is there a way to close the thread as it is not useful anymore :) )

Homework Statement I need to find the X of two substances using only the data found in lab. Which is: nmixture=1.4156 nbutan-2-one=1.3787 ntoluene=1.4970 For the mixture, I don't know what X (the mole fraction) is. That is what I must find out. Homework Equations nmixture= (Xbutan-2-one...

Thank you! It works now, my mistake was simply that I forgot to take the sqrt of sec^2

I can officially say that it works now! Thank you Faris! Such a "minor" mistake that really changed everything in the problem!

Ok, I'm currently trying, correcting the mistake I made with my sec^2. It looks good!

Thank You Mark! I'm still learning to use Latex... I changed it and it should appear ok, now!

No problem! I tried using Latex, but it doesn't work...It's #6

I'm trying to find the integral of the equation, but it doesn't give the same answer as the one I'm supposed to get, and I don't know what I'm doing wrong. I'm using trigonometric substitution which let's x=4sinΘ.

Homework Statement Integral of $$ x^3\sqrt{x^2+16}dx $$ answer should give $$ 1/5(x^2+16)^{5/2} -16/3(x^2+16)^{1/2}+C $$ Homework Equations x=atanθ The Attempt at a Solution Mod note: The integral is ##\int x^3 \sqrt{x^2 + 16} dx## The published answer is ##1/5(x^2+16)^{5/2}...

Whoa didn't know that thanks!

This is what I finally did! Thank you again!

Oh ok! I think I get now! Thank you to everybody on this thread for your help! I'll try that!

Wel, normally you try going the other way around, but it still doesn't work as shown in the first picture...