Recent content by Akhilleus

Ah, I see. This was a LOT easier than I was making it... haha. I was caught up on the idea that the distance traveled would contract if he was traveling at 0.6c, and thought that if he didn't slow down, event B would happen behind him. I'm very intrigued by the effects of relativity but I'm...

Using the distance between the two events divided by the time (5 microseconds) as V: V = 1000m/(5 E-6)s = 2E8 m/s g = 1/√(1 - (2E8)2/c2) = 1.8 x' = 1.8(1000m - (2E8)(5E-6)) = 0 So V is the speed of the moving observer as seen by a hypothetical second person at rest. Here, V is just...

Homework Statement Event A occurs at xA = 500m. Event B occurs 5 microseconds later at xB = 1500m. With what speed must an observer move in the positive x direction so that the events occur at the same point in space in the observer's frame?Homework Equations Lorentz transformation...

Excellent! Thanks for your help.

Ah, that makes sense! Thank you! Just to double check, I got for an answer: i = Voeiwt (iwC + 1/R) Does it matter that there's also an i in the exponent?

RIGHT that's what I meant. Is that my answer (solving for i) or do I set that equal to I/C and solve for I? I guess I'm getting hung up on the fact that there's an instantaneous current (i) and an average/overall current (I), and I don't know which to solve for.

Is the i in the voltage function V = Voeiwt the current I want? If so, I've been spending MUCH longer on this than I needed to... haha In that case, it'd just be: V = Voeiwt dV/di = Vo(iwt)eiwt

I've gotten as far as: i = C*dV/dt + V/R Is it mathematically correct to say that V is common to both terms on the right, and therefore: i = V(C*d/dt + 1/R) ? If so, I would plug in the V value given in step (b): i = Voeiwt(C*d/dt + 1/R) How would I go about integrating this...

Homework Statement I am given an RC circuit with an alternating current. The circuit contains a capacitor and a resistor in parallel. Part (a) says "Use KCL to find a differential equation for I in terms of V." Part (b) says "For an applied voltage V = Voexp(iwt), find the current I."...