Recent content by alariv8

I'll make another update to my post. Now I'm switching from physics to modern neuroscience and I have more experience with tablets and ereadrers now. : I agree if you like to read often mathematics texts from small screens, but I don't see why I would rather choose an iPad over my Lenovo...

I will update now my post. I just saw a fellow course mate today -- he is studying from Amazon Kindle e-reader. The quality seemed really fine and I asked him if there were any problems with files. He said that he doesn't experience any format problems -- pdf's can easily be opened and read. He...

Hey. I am studying thph at the University of Helsinki and I also recently bought a tablet, mainly for study related purposes, but the buy was also facilitated by my health issues, so the decision was firm and clear. I did a bit of research a few years ago about tablets and e-readers and I am...

Okay, I think I got it already, the cone stuff is relatively easy. It was all about the limits of the integrals, I needed no more specific integrand than dzdydx. Great. The graph still needs to be created. Not difficult probably.

Firstly, I tried to calculate the volumes of the cones, the cylinder volume is easy (no integration needed?). I tried the following expression: Integrate[2 [l/R] Sqrt[x^2 + z^2], {x, 0, R}, {z, -Sqrt[R^2 - x^2], Sqrt[R^2 - x^2]}, {y, Sqrt[x^2 + z^2], l}, Reals] Simplify[%] But...

Homework Statement Create a function MyContainer[R, L, l, H] in the program 'Mathematica' to determine the capacity of fluid in the container according to the given filling height H. The container is a cyclinder with cones on both sides. The arguments of the function MyContainer[R, L, l, H]...

I figured even integration by parts wasn't necessary, only a change of variable. I passed the exam and the professor did not find any mistakes in my integrals. There is a chance that at least r^(-2) expectation value formula with quantum numbers may be slightly faulty. I did not have time...

I think understand the divergence problem, quite simple actually. Integrating by parts gives Gamma(0), because one can show, that u*v limits to 0, so no recurrence relation for Gamma function needed at all, because modulus of Gamma(0) tends to infinity PS! I was also right at the...

Yeah, I knew it would settle down for Gamma function. If I got it then: When to reparametrize r=r0t and calculate, we get the definition of Gamma function. Because in my problem, n was -1, I would have to calculate Gamma(-1). It's modulus is +infinity, because Gamma(n)= [Gamma(n+2)]/[n*(n+1)]...

Hydrogen atom: 1/(r^2 )2p state constant problem //1/(r^3) exp. value Homework Statement Hello, I am new to this forum. I hope it is all right I uploaded problems as image files (in handwriting). I calculated all (r^(-1), r^(-2) and r^(-3) expectation values for Hydrogen atom for 1s and...