Recent content by alex.pasek
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Canoe and Man Motion: Finding the Relationship Between Distance Traveled
The distance the man walks minus the change in the center of mass (in the boat's frame)?- alex.pasek
- Post #19
- Forum: Introductory Physics Homework Help
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Canoe and Man Motion: Finding the Relationship Between Distance Traveled
So, if in the lake's frame the CM of the man and the boat does not move even if they do. This may suggest the displacement of the man is somehow proportional to the boat's? I mean, if the man walks to the right, then the boar moves to the left?- alex.pasek
- Post #17
- Forum: Introductory Physics Homework Help
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Canoe and Man Motion: Finding the Relationship Between Distance Traveled
I do not understand what is actually happening within the lake's reference frame. I do not know where is the origin for that frame :(- alex.pasek
- Post #15
- Forum: Introductory Physics Homework Help
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Canoe and Man Motion: Finding the Relationship Between Distance Traveled
What if I tried a different approach, as CMo=CMf=1.43 m And calling the displacement "x"; 1.43 ⋅ 120 m⋅kg = 55 ⋅ 3.25 m⋅kg + 65 ⋅ x kg ; solving for x i get x ≈-0.11 m And this would be the displacement of the canoe, I think.- alex.pasek
- Post #13
- Forum: Introductory Physics Homework Help
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Canoe and Man Motion: Finding the Relationship Between Distance Traveled
The conoe does not move? :oldeek:- alex.pasek
- Post #11
- Forum: Introductory Physics Homework Help
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Canoe and Man Motion: Finding the Relationship Between Distance Traveled
I think the momentum is conserved, no externa forces are acting on the system.- alex.pasek
- Post #9
- Forum: Introductory Physics Homework Help
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Canoe and Man Motion: Finding the Relationship Between Distance Traveled
So, If I applied the reference frame, I guess I should undo it. Then by substracting it to each center of mass I should be given the result; so: dcanoo= (xocanoo-ΔCM)= (2 - 1.14)m = 0.86 m Would it be correct?- alex.pasek
- Post #7
- Forum: Introductory Physics Homework Help
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Canoe and Man Motion: Finding the Relationship Between Distance Traveled
Sorry :frown: Here goes the complete reasoning; CMo=(1/M)⋅∑xn ⋅ mn= (1/120 kg)⋅[(55⋅0.75 kg⋅m)+(65⋅2 kg⋅m)] = 1.43 m CMf=(1/M)⋅∑xn ⋅ mn= (1/120 kg)⋅[(55⋅ 3.25 kg⋅m)+(65⋅2 kg⋅m)] = 2.57 m And calculate ΔCM=CMf-CMo= (2.57-1.43)m = 1.14 m Would be this the displacement of the boat?- alex.pasek
- Post #5
- Forum: Introductory Physics Homework Help
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Canoe and Man Motion: Finding the Relationship Between Distance Traveled
So; I should compute CMo = CMf? CMo=(1/M)⋅∑xn ⋅ mn CMf=(1/M)⋅∑xn ⋅ mn And calculate ΔCM=Cf - Co With this I get ΔCM= -0.33 but I do not know how to proceed forward.- alex.pasek
- Post #3
- Forum: Introductory Physics Homework Help
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Canoe and Man Motion: Finding the Relationship Between Distance Traveled
Homework Statement A 55 kg man is standing on a 65 kg and 4.0 m length canoe that floats without friction on water. The man walks from a 0.75m from one end of the canoe to another point 0.75 from the other end of the canoe. What distance does the canoe move? Homework Equations Center of mass...- alex.pasek
- Thread
- Center Center of mass Mass
- Replies: 19
- Forum: Introductory Physics Homework Help
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What is the total flux of F across the given surface S?
Thank you very much! :)- alex.pasek
- Post #6
- Forum: Calculus and Beyond Homework Help
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What is the total flux of F across the given surface S?
Homework Statement Considering the vector Field F(x,y,z))(zx, zy, z2), and the domain whose boundary is provided by S=S1∪S2 with exterior orientation and S1={(x,y,z)∈ℝ3 : z=6-2(x2+y2), 0≤z≤6}, S2={(x,y,z)∈ℝ3 : z=-6+2(x2+y2, -6≤z≤0}. Compute the total flux of F across S. Homework Equations...- alex.pasek
- Thread
- Flux Net Surface
- Replies: 5
- Forum: Calculus and Beyond Homework Help