Recent content by alex.pasek

  1. alex.pasek

    Canoe and Man Motion: Finding the Relationship Between Distance Traveled

    The distance the man walks minus the change in the center of mass (in the boat's frame)?
  2. alex.pasek

    Canoe and Man Motion: Finding the Relationship Between Distance Traveled

    So, if in the lake's frame the CM of the man and the boat does not move even if they do. This may suggest the displacement of the man is somehow proportional to the boat's? I mean, if the man walks to the right, then the boar moves to the left?
  3. alex.pasek

    Canoe and Man Motion: Finding the Relationship Between Distance Traveled

    I do not understand what is actually happening within the lake's reference frame. I do not know where is the origin for that frame :(
  4. alex.pasek

    Canoe and Man Motion: Finding the Relationship Between Distance Traveled

    What if I tried a different approach, as CMo=CMf=1.43 m And calling the displacement "x"; 1.43 ⋅ 120 m⋅kg = 55 ⋅ 3.25 m⋅kg + 65 ⋅ x kg ; solving for x i get x ≈-0.11 m And this would be the displacement of the canoe, I think.
  5. alex.pasek

    Canoe and Man Motion: Finding the Relationship Between Distance Traveled

    I think the momentum is conserved, no externa forces are acting on the system.
  6. alex.pasek

    Canoe and Man Motion: Finding the Relationship Between Distance Traveled

    So, If I applied the reference frame, I guess I should undo it. Then by substracting it to each center of mass I should be given the result; so: dcanoo= (xocanoo-ΔCM)= (2 - 1.14)m = 0.86 m Would it be correct?
  7. alex.pasek

    Canoe and Man Motion: Finding the Relationship Between Distance Traveled

    Sorry :frown: Here goes the complete reasoning; CMo=(1/M)⋅∑xn ⋅ mn= (1/120 kg)⋅[(55⋅0.75 kg⋅m)+(65⋅2 kg⋅m)] = 1.43 m CMf=(1/M)⋅∑xn ⋅ mn= (1/120 kg)⋅[(55⋅ 3.25 kg⋅m)+(65⋅2 kg⋅m)] = 2.57 m And calculate ΔCM=CMf-CMo= (2.57-1.43)m = 1.14 m Would be this the displacement of the boat?
  8. alex.pasek

    Canoe and Man Motion: Finding the Relationship Between Distance Traveled

    So; I should compute CMo = CMf? CMo=(1/M)⋅∑xn ⋅ mn CMf=(1/M)⋅∑xn ⋅ mn And calculate ΔCM=Cf - Co With this I get ΔCM= -0.33 but I do not know how to proceed forward.
  9. alex.pasek

    Canoe and Man Motion: Finding the Relationship Between Distance Traveled

    Homework Statement A 55 kg man is standing on a 65 kg and 4.0 m length canoe that floats without friction on water. The man walks from a 0.75m from one end of the canoe to another point 0.75 from the other end of the canoe. What distance does the canoe move? Homework Equations Center of mass...
  10. alex.pasek

    What is the total flux of F across the given surface S?

    Homework Statement Considering the vector Field F(x,y,z))(zx, zy, z2), and the domain whose boundary is provided by S=S1∪S2 with exterior orientation and S1={(x,y,z)∈ℝ3 : z=6-2(x2+y2), 0≤z≤6}, S2={(x,y,z)∈ℝ3 : z=-6+2(x2+y2, -6≤z≤0}. Compute the total flux of F across S. Homework Equations...
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