Recent content by alex91alex91alex

Could really use some insight, thank you.

Oh, found out that v=rω so v=0.0567m(14.1rad/s)=0.8m/s So, KE(block) = PE(spring) =>1/2mv^2 = 1/2kA^2 (1/2)(0.425kg)(0.8m/s)^2=(1/2)(84.6N/m)(A^2) A=sqr(23.0112)=4.80m That does not seem right...

Homework Statement A 425 gram mass is attached to a horizontal spring. The spring is known to have a spring constant of 84.6 N/m. The mass is free to slide along a friction less surface. a) The mass is then pulled to the side a distance of 5.67 cm and released. Determine the period and...

Ok, so let's says the center of rotation is the left end point. 10.2N(0.02m)+19.4N(0.3m-0.074m)=(10.2N+19.4N)x 10.2N(0.02m)+19.4N(0.226m)=29.6N*x x=0.155m is that right?

Hmm, would the mg of the box be CW or CCW?

The total weight would be (10.2N+19.4N)/g=3.02kg, right?

Homework Statement A non-uniform box sits on two scales as seen below. Scale A reads 10.2N, and scale B reads 19.4N. Question: How far from the left end of the box is the center of mass located? Homework Equations τccw=τcw τ=f*d(from pivot point) The Attempt at a Solution If I choose the...

That is going to wield t= 0.02739s and 0.1187s, does not feel right though because a period takes 0.183secs.

So cos( (34.4 rad /s)t+ π/5 ) need to equal 0? (34.4rad/s)t+π/5 has to be equal to π/2 or 3π/2?

Homework Statement I am having issues with d) and would like to know if I did the a, b, and c correctly. I have tried to look online for explanation but with no success. A harmonic oscillator executes motion according to the equation x=(12.4cm)cos( (34.4 rad /s)t+ π/5 ) . a) Determine the...

So, since my derivatives are correct I should get: x0= -1.237 cm x2.67=-2.43 cm v0=-1.881 cm/s v2.67=1.43 cm/s^2 a0=0.67 cm/s^2 a2.67=1.66 cm/s^2 j0=0.537 cm/s^3 j2.67=0.2 cm/s^3 Would the results be correct now?

Oh, I see what you mean. I had my notes wrong. Thanks for the clarification.

So I had a test and this was the only exercise I miss points at and I can not understand why, I did everything according to my class notes. A particle moves according to the following equation: x=( −0.00521 cm/s^4 ) t^4 +( 0.0895 cm/s^3 ) t^3 + ( 0.335 cm/s^2 ) t^2−( 1.881 cm/s ) t−1.237 cm...