Recent content by amninder15

so now if I was to write Z I get 1 1 0 1 1 0 therefore Z is repeating 110 thus, 60/3 gives 20 MHz am I on right track?

Hi I got this question on midterm. the correct answer is 20 MHz. But I am getting 10 MHz. I attached a text file which shows all the work I done. Can someone please explain this question and tell me where I am doing it wrong. Thanks

Can someone help me with this question? I know we have to set up the auxiliary equation and then solve for λ but for some reason I am not getting the right answer. My equation is: m^2 + 4m + (5λ + 3) = 0 then we get -2 ± sqrt(5λ-1)i Now can somebody explain what I have to do...

For this question Why is the answer not m(0,1)? Little confused here. Any help will be appreciated. Thanks

ohh yea got it thanks a lot. cheers

Can anyone help me with this question? I got the equation of the 2to 1 MUX. I got F = A'B' + AC. But the problem is I am not sure how to convert this into 4:1 MUX. Any help will be appreciated. Thanks

I can't seem to get the right answer for this question I am thinking (250+470) in parallel with 940. Can someone please explain me this question?

Here is the question

Hi can someone please elaborate on the explanation our teacher gave us.

Yea I made some silly mistake I think It goes from sin^-1(1/3) to Pi-sin^-1(1/3). But that looks ugly. Am I on right path.

Can someone please help me on this question. I tried to solve it by integrating 0.5*(1-3sin(θ)^2 from -Pi/2 to 0 but I didnt get the answer.

Yea I did made a mistake. Now everything looks good. So this is my final matrix now [1 1 0 | 7/4] [0 0 0 | 0] [0 0 1 | -1/4] so that implies y = s, x = 7/4 -s and z = -1/4. Thanks for your help really appreciate it.

Ok so this is what I am doing I used the row reduction method and I found this [0 0 0 | -7/4] [0 0 1 | -1/4] [1 1 0 | 7/4] But now the problem again is same if you look at the first row it clearly implying 0 = -7/4 which is absurd so doesn't it mean that the system is...

I am having trouble solving this problem. Since in order to solve for x we need to find (A^-1)B but the problem is that in order to find A^-1 when we do the determinant I get 0 so that implies it is inconsistent. I am not sure I have the right approach to this question. Any help will be...

Thank You So much I have exam tommorow and this was question in practise exam and I wasnt able to do it. But you explained it real nice Thanks!