Recent content by an_mui

T1 is the temperature of substance 1 (i think that should be the temperature of the corpse), T2 should be the temperature of the air. k1 and k2 are constants which depend on the heat absoprtion propertiies of the substances.

there is no actual problem because my teacher only wants us to explain how the above equations can be used in criminological applications to estimate the time of death of a discovered corpse. But I really don't know what we are solving for in this case. I tried researching on the internet but...

Hey I need help from this as soon as possible. My teacher has given me 2 equations and I need to use them to estimate the time of death of a discovered corpse. 1. \frac {\Delta T_{1}}{\Delta t} = -k_{1}(T_{1} - T_{2}) 2. \frac {\Delta T_{2}}{\Delta t} = -k_{2}(T_{2} - T_{1}) I think...

i tried and i really can't see what step i can take next.

so the force on a charged particle q in an electric field E Fnet = eE equation 1: 0.5(-eE/mp)t^2 equation 2: 0.05 - 0.5(eE/m)t^2 i am sorry but i still dont' know how to find the electric field.

hm how can i solve the problem without actual numbers given in the equation?

Two large parallel copper plates are 5.0cm apart and have a uniform eletric field between them as shown below. An electron is released from the negative plate at the same time that a proton is released from the positive plate. Neglect th force of the particles on each other and find their...

is E equal to ... E = (kQ1Q2) / (Q2L cos (theta))^2 + mgcos (theta) / Qsin (theta)?

hm . i still got 37 and 53 degrees using your method, i guess i might've calculated my A value wrong then. this is what i got. R = 2 Vo^2 sin (theta) cos (theta) / gelec R = 1.27 x 10^-3 gelec = |Felec| / mass = |qfield x E| / m = (1.6 x 10^-19)(720) / 1.67 x 10^-27 = 6.898...

We are to express the answer in terms of m, L, Q , theta, g and k, so we aren't given any numbers. However, my teacher said the two unknowns in this equation are Tension and the electric field intensity

yes i am sure the two charges are equal and opposite.

Protons are projected with an initial speed of v0 = 9550 m/s into a region in which a uniform electric field E = 720N/C [down] is present. The protons are to hit a target that lies a horizontal distance of 1.27mm from the point at which the protons are launched. a) find the two projection...

Any help on this question is appreciated. Two small spheres each of mass m are suspended by light strings of light L. A uniform electric field is applied in the x direction. If the spheres have equal and opposite charges of magnitude Q, determine the electric field intensity that enables the...

Sorry i thought I did what you said above. I simplified everything except for the first term and the constant. However, I ended up with log x = 3 or log x = -9.

If (log x)^2 + log x^3 - 27 = log x^4 - log x^7, solve for x to 2 decimal places (log x)^2 + log x^5 - 27 = log x^4 - log x^7 (log x)^2 + 6 log x - 27 = 0 Let log x be a a^2 + 6a - 27 = 0 (a + 9)(a - 3) = 0 a = 3 or - 9 log x = 3 or log x = -9 ... x = 10^3 or 10^-9 Please...