Recent content by angel_eyez

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    How Do You Calculate the Integral of e^x from 0 to 1 Using Riemann Sums?

    Reimann's Law..maajoor Helpp! 1. Use Riemann sum ( do NOT use fundamental theorum of Calculus) to calculate (integral) b= 1 and a =0 e^x dx Attempt: (delta x)=b-a/n 1-0/n =1/n xi = 1/n (integral) b=1 a=0 sigmaf(xi)deltax limn->infin sigma f(i/n)1/n use eqn to get...limn->infin...
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    How can I solve limx->infinity (x/x+1)^x using L'Hospital's rule?

    kk thnnxx for your help newayzz =)
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    How can I solve limx->infinity (x/x+1)^x using L'Hospital's rule?

    noo i haven't :|
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    How can I solve limx->infinity (x/x+1)^x using L'Hospital's rule?

    i took the ln of both sides, and then found the derivative, and i got the answer as zero.. so i got ln y= 0 den i used the fact that e^lny = y...there fore y= e^0 =S..
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    How can I solve limx->infinity (x/x+1)^x using L'Hospital's rule?

    noo..havent learned it =S
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    How can I solve limx->infinity (x/x+1)^x using L'Hospital's rule?

    umm so when x is large 1/x = 0 so that means e^o = 1, I am still lossttt
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    How can I solve limx->infinity (x/x+1)^x using L'Hospital's rule?

    l'hospitals rulee! major help 1. i don't know how to do this question limx->infinity (x/x+1)^x. i keep gettin the rong answer, some heelp pleasez:confused: 2.the right answer is 1/e but I am not getting that, i tried many diff ways, i can't post my work it here because its too long...
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    Another le chatelier qsneed to make sure

    1. for the equilibrium reaction below predict what would happen if dilute HCl were added to the K2CrO4 solution? 2. 2CrO4(aq) + 2H+(aq) <--> Cr2O7(aq) + H2O 3. The reaction will shift to the right because the acid will donate a proton which will react with H+ to produce hydrogen...
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    Effect of Adding NaOH to a Solution of K2CrO4 at Equilibrium

    um..yeaaa..:|
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    Effect of Adding NaOH to a Solution of K2CrO4 at Equilibrium

    ohhh..k..so wen NaOH is added it takes up the proton since its a base..so therefore the reaction will proceed to the left =)
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    Effect of Adding NaOH to a Solution of K2CrO4 at Equilibrium

    btw ye i know it needs to be a double arrow, i just didnt know how to put it
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    Effect of Adding NaOH to a Solution of K2CrO4 at Equilibrium

    so basically da H+ is the acid..cuz acids donate a proton..so therefore the reactino will proceed in the forward direction to reduce the stress of NaOH...? need to know if I am right =)
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    Effect of Adding NaOH to a Solution of K2CrO4 at Equilibrium

    neutralization reaction?..so that means the reaction will proceed in the forward direction?
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    Effect of Adding NaOH to a Solution of K2CrO4 at Equilibrium

    Le chatelier's principle..HELP! 1. for the given reaction at equilibrium predict what would happen if NaOH were added to a solution of K2CrO4 2. 2CrO4 (aq) + 2H+(aq) --> Cr2O7(aq) + H2O 3. my answer was that it would not affect the equilibrium since NaOH is a liquid :confused...
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    How can the constant and x^12 terms be found in the expansion of (3/x - x^3)^8?

    i still kind adont get it..can u please complete it:blushing: