That answer is incorrect..that is why I posted it...I can't find the correct answer..I was just showing my work so someone could tell me where I went wrong...Does anyone know??
...I got it..I shouldn't have the parenthesis around the 3*200, since only the 200 is squared...
Homework Statement
Water is leaking out of an inverted conical tank at a rate of 6500 cm3/min at the same time that water is being pumped into the tank at a constant rate. The tank has height 6 m and the diameter at the top is 4 m. If the water level is rising at a rate of 20 cm/min when the...
I am not sure if I am doing this right.
I plugged in:
320-45-006=16.667t+ 1/2(3.086)t^2
for t I found it to be 3.886 then I added the 5.4sec already passed and got 9.286sec...does that sound correct, or am I not understanding.
I don't know if I have...is x= to distance? In different books and sites they use different variable to represent distance, whether it be s, d or x.
if that is the case would I rearrange it to solve for t?
2(X-Xsub0)/(Vsub0+a)??
A hot rod can accelerate from 0 to 60 km/h in 5.4 s.
(a) What is its average acceleration, in m/s2, during this time?
(b) How far will it travel during the 5.4 s, assuming its acceleration is constant?
(c) How much time would it require to go a distance of 0.32 km if its acceleration...
Thank you JonF...the cos(90 + theta)= sin theta was in my text as a trig equation to use...I didn't make it up...I know that the derivative of cos is -sin and the derivative of sin is cos, and tan is sec^2...I get all the derivative stuff..Just seem to have an issue with the basics, which to me...
Given sinθ = 0.6, calculate tanθ without using the inverse sine function, but instead by using one or more trigonometric identities. You will find two possible values.
I found one of the values using sin^2 (theta) + cos^2 (theta) = 1
I tried using cos (90 + theta)= sin theta to find the...
Given sinθ = 0.6, calculate tanθ without using the inverse sine function, but instead by using one or more trigonometric identities. You will find two possible values.
I found one of the values using sin^2 (theta) + cos^2 (theta) = 1
I tried using cos (90 + theta)= sin theta to find the...
First off, thank you for responding so quickly...
I drew a diagram and labeled the sides, then I used sin and cos to find the sides a and b...I got sin (20)= b/4 and cos (20)= a/4...found b= 1.3681 and a= 3.75878...the computer marked my answers wrong...
I need help...
I am taking physics for the first time and I am taking it online which probably isn't the smartest way to go...but to make matters worse I am also currently enrolled in the calculus class that is a prerequisite for the course at the same time so my math skills are not really up...