Recent content by annoymage

yes, yes, that's it ! thanks !

Hi, I've heard of this one name, or rather it's a name of language that they use on chatting or using password, that goes like changing a to @, o to (), s to $, etc etc. Anyone knows what is the name of that thing?

Firstly, where do I have to post if i have a question on LaTeX? and here's the question, \vdash_{A} how do I make that subscript exactly below the line - on that simbol?

Hi, I am planning to take my master next year, I have several misunderstanding that I wish anybody can explain. Okay, at first, last year, I've been checking Master programme on Universities. I found that some of them distinguished Master by research and master by coursework. And I keep...

Theorem : let A be a set of formulas, a be a formula For all A and all a, Every interpretation which is a model of A is also a model of a iff not (Sat A) U {~a} Proof Every interpretation which is a model of A is also a model of a iff(1) there is no interpretation which is a model of A but...

it's a theorem, not definition

hmm, you know xg-1 in in the kernel, then (xg-1)g is in {kg | k ∈ ker i}, so this conclude that i^−1(h) is subset of {kg | k ∈ ker i}. now left to show is {kg | k ∈ ker i} subset of i^−1(h)

hmm, may i ask what trivial homomorphism means?

let x be the preimage of h, ie: i(x)=h=i(g), then i(xg-1)=e, then what can you say about x??

Z12 are group on operation addition, not multiplication

you mean this right? A=\{n\in \mathbb{Z}~\vert~n> c\} thanks you soo much

hmm then i got m-1 \leq c \leq m it's not the same as m-1 \leq c<m right?

Homework Statement let a,b be positive integer , c is real number, and -a<c<b i want to show there exist integer m, -a \leq m \leq b such that m-1 \leq c<m i don't know any easy method, but this is where i got now, Let set S=[m|-a \leq m \leq b] So by contradiction, suppose that for all m...

thank you very much

aaaaaaaaaaaarghh, yes yes, thank you ^^ hmm, now i have to prove that (a_n) is convergent, i suspect i should prove that (a_n) is bounded then, i know (a_n) is monotone then, (a_n) must be converging right? then continue like i was doing above right?