Recent content by AnonBae
-
A
Calculating the Charge on Capacitor
I figured it out! The voltage of the 1500 ohm resistor is the same amount that charged up the 100 microfarad capacitor. Thank you so much for the help :smile:- AnonBae
- Post #8
- Forum: Introductory Physics Homework Help
-
A
Calculating the Charge on Capacitor
Oh. Okay For the loop specified, Each potential drop will sum to the emf or the 55 V battery. So, since 55 V = I*525 + I*1500 + I*100, since current in the same everywhere in a series loop. Thus, current would be after simplification around 0.026 from sig. figs. So V1 would be 13.65, V2 = 39...- AnonBae
- Post #7
- Forum: Introductory Physics Homework Help
-
A
Calculating the Charge on Capacitor
The voltage across the branch containing the 100 μF capacitor should be 55 V, stored in the capacitor. I am not quite understanding what you mean by measuring the voltage at the open terminals. At the open terminals, the voltage would drop depending on which resistor comes before it?- AnonBae
- Post #5
- Forum: Introductory Physics Homework Help
-
A
Calculating the Charge on Capacitor
The current will be flowing through the branches that do not have the capacitors, or the 525, 100, and 1500 resistors, which I did say in the original post. How will this help though in determining the charge of the capacitor if it's already fully charged? Like Q = C * V, but that does not give...- AnonBae
- Post #3
- Forum: Introductory Physics Homework Help
-
A
Calculating the Charge on Capacitor
Homework Statement The circuit has been completed for several minutes. Suppose that ε = 55 V . Calculate the magnitude of charge on the 100 μF capacitor plate. Homework Equations Q = C * V The Attempt at a Solution Since the capacitors have been fully charged, current has stopped flowing at...- AnonBae
- Thread
- Capacitance Capacitor Charge
- Replies: 8
- Forum: Introductory Physics Homework Help
-
A
Electric field acting on a negative test charge due to semicircular rod
Homework Statement A thin semicircular rod is broken into two halves. The top half has a total charge +Q uniformly distributed along it, and the bottom half has a total charge -Q uniformly distributed along it. A negative test charge is placed at points A, B, and C. *Image attached* Consider...- AnonBae
- Thread
- Charge Electric Electric field Field Negative Rod Test
- Replies: 3
- Forum: Introductory Physics Homework Help
-
A
Electric field at a point (point charge and semi-circle rod)
a. I do know that a fractional charge of +Q contributes to the electric field at point C since no other electric field lines cross through point C besides the one horizontal to point C. I am confused as to whether that fractional charge offsets its weak electric force by the formula for the...- AnonBae
- Post #3
- Forum: Introductory Physics Homework Help
-
A
Electric field at a point (point charge and semi-circle rod)
Homework Statement A thin semicircular rod has a total charge +Q uniformly distributed along it. A negative point charge -Q is placed as shown. (Point C is equidistant from -Q and from all points on the rod.) *Image Attached* Let Ep and Er represent the electric fields at point C due to the...- AnonBae
- Thread
- Charge Electric Electric field Field Point Rod
- Replies: 3
- Forum: Introductory Physics Homework Help